The function below prints each number twice. Could someone explain how it works? I tried debugging but all I can see is that the value of i only increases on every second iteration.

async function run(then) {
    for (let i = 1; i <= 10; i++) {
        console.log(i);
        then = await { then };
    }
}

run(run);

Concretely speaking, there are two things I don't understand.

• Why does i not increase on every single iteration?
• What does then = await { then }; exactly do? My first guess was that it would wait for a nested async call to run to finish before moving on to the next iteration, but this does not seem to be the case.