I want to sort this array by its xp object:
[
["438449925949489153", {
"xp": 2
}],
["534152271443415140", {
"xp": 3
}],
["955210908794236938", {
"xp": 1
}]
]
So that it returns this array:
[
["955210908794236938", {
"xp": 1
}],
["438449925949489153", {
"xp": 2
}],
["534152271443415140", {
"xp": 3
}]
]
I've tried to do this with the sort-json npm module but it sorted the first value instead of xp
const sortJson = require('sort-json');
sortJson(array)
You can just use the native sort:
let data = [
["438449925949489153", {
"xp": 2
}],
["955210908794236938", {
"xp": 3
}],
["955210908794236938", {
"xp": 1
}]
];
const ascending = (a,b) => a[1].xp - b[1].xp;
const descending = (a,b) => b[1].xp - a[1].xp;
data.sort(ascending);
console.log(data)
data.sort(descending);
console.log(data)Notice that sort mutates the original array: if you don't want to do that, you need do perform a shallow copy of the original array.
sort descending:
arr.sort((a,b) =>{
if (a[1].xp < b[1].xp) return 1
else return -1
})
sort ascending:
arr.sort((a,b) =>{
if (a[1].xp < b[1].xp) return -1
else return 1
})
I would suggest a bit more clean implementation:
function compare( a, b ) {
if ( a[1] < b[1]){
return -1;
}
if ( a[1] > b[1] ){
return 1;
}
return 0;
}
arr.sort( compare );
Or one-liner:
arr.sort((a,b) => (a[1] > b[1]) ? 1 : ((b[1] > a[1]) ? -1 : 0))