Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

357
Vistas
Iterate Object and replace values

I have this Object:

{
  "data": {
    "success": true,
    "historical": true,
    "date": "2022-01-01",
    "base": "MXN",
    "rates": {
      "COFFEE": 0.02158734144632395,
      "CORN": 0.008232645172711363,
      "COTTON": 0.04320921676820366,
      "SOYBEAN": 0.0036714622235960175,
      "SUGAR": 0.25680398615582695,
      "WHEAT": 0.00017592643558262669
    },
    "unit": "per bushel"
  }
}  

And I want to iterate over "rates" to replace the values of each key with 1 / value
I tried with: (prueba is the Object name)

Object.values(this.prueba.data.rates).forEach((val) => {
      console.log(val)
      val = 1 / val;
      console.log(val)
    })

But how to replace those values or how can I saved them in another array or Object

about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

Your code doesn't work because the change you made to val is only reflected within the scope of the callback.

You should instead loop through each property and set its value.

const obj={data:{success:!0,historical:!0,date:"2022-01-01",base:"MXN",rates:{COFFEE:.02158734144632395,CORN:.008232645172711363,COTTON:.04320921676820366,SOYBEAN:.0036714622235960175,SUGAR:.25680398615582695,WHEAT:.00017592643558262669},unit:"per bushel"}};

let r = obj.data.rates;
Object.keys(r).forEach(e => r[e] = 1 / r[e])
console.log(obj)

If you're using Typescript it's necessary to declare the object like so:

const obj: {[key: string]: any} = ...
about 4 years ago · Juan Pablo Isaza Denunciar

0

You can iterate over Object.entries (or Object.keys) and replace the value for each key.

let obj={data:{success:!0,historical:!0,date:"2022-01-01",base:"MXN",rates:{COFFEE:.02158734144632395,CORN:.008232645172711363,COTTON:.04320921676820366,SOYBEAN:.0036714622235960175,SUGAR:.25680398615582695,WHEAT:.00017592643558262669},unit:"per bushel"}};
Object.entries(obj.data.rates).forEach(([k, v]) => obj.data.rates[k] = 1 / v);
console.log(obj);

about 4 years ago · Juan Pablo Isaza Denunciar

0

I think it will be cleaner to write it explicitly using for loops:

let obj = {} //original object stated in question
let obj2 = Object.create(null);//DON'T just use {}, see below
for(let productName in obj.data.rates){
   let inverse = 1/obj.data.rates[productName];
   //to edit the object directly
   obj.data.rates[productName] = inverse;
   //to add to another object
   obj2[productName] = inverse;
}

The difference between {} and Object.create(null) can be found here

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda