I have a multiline stock. How can I remove a specific line?
const str = `
import 'C:\Users\Desktop\sanitize.js';
val = ln + '\t';
val += lc + '\t';
val += f + '\t';
val += id + '\t'; // id source
val += sc + '\t\n';
`;
In this case, I need to delete lines where Import or reguired occurs, while maintaining line breaks.
My approach doesn't work, because there can be a line break inside the lines, and I'm trying to split the line by line breaks in order to achieve the result.
function sanitizeSandbox(code) {
let disinfectedSandbox = '';
if (typeof code === 'string' && code.length > 0) {
const sandboxSplit = code.split('\n');
for (const str of sandboxSplit) {
if (!str.includes('import') && !str.includes('required')) {
disinfectedSandbox += `${str}\n`;
}
}
}
return disinfectedSandbox;
}
Expected value:
`
val = ln + '\t';
val += lc + '\t';
val += f + '\t';
val += id + '\t'; // id source
val += sc + '\t\n';
`
The value I get with my approach:
`
val = ln + '\t';
val += lc + '\t';
val += f + '\t';
val += id + '\t'; // id source
val += sc + '\t
\n';
`
You can use this regex (derived from this answer):
(?:[^\n']|'[^']*')+
to match lines in your string (while ignoring newlines within ''), then filter based on whether or not the line contains import or required:
const str = `
import 'C:\Users\Desktop\sanitize.js';
val = ln + '\t';
val += lc + '\t';
val += f + '\t';
val += id + '\t'; // id source
val += sc + '\t\n';
`;
result = str.match(/(?:[^\n']|'[^']*')+/g)
.filter(l => !l.match(/\b(import|require)\b/))
.join('\n')
console.log(result)
console.log(JSON.stringify(result))