Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

384
Vistas
I can't get rid of this problem while working with gulp file TypeError: Cannot read properties of undefined (reading 'pipe')

I am trying to setup my gulpfile for future projects and on the firt stage bumped into a problem that accompanies me no matter what do I do with my code: Here it is :

"TypeError: Cannot read properties of undefined (reading 'pipe')
    at pipe (D:\HTML\NodeJs\Gulp\src\node_modules\pump\index.js:56:15)
    at Array.reduce (D:\HTML\NodeJs\Gulp\src\node_modules\ometa\lib.js:101:9)
    at pump (D:\HTML\NodeJs\Gulp\src\node_modules\pump\index.js:79:11)
    at Pumpify.setPipeline (D:\HTML\NodeJs\Gulp\src\node_modules\pumpify\index.js:39:5)
    at new Pumpify (D:\HTML\NodeJs\Gulp\src\node_modules\pumpify\index.js:15:30)
    at Function.Pumpify [as obj] (D:\HTML\NodeJs\Gulp\src\node_modules\pumpify\index.js:13:44)
    at globStream (D:\HTML\NodeJs\Gulp\src\node_modules\glob-stream\index.js:73:18)
    at Gulp.src (D:\HTML\NodeJs\Gulp\src\node_modules\vinyl-fs\lib\src\index.js:24:5)
    at operationsWithJsFiles (D:\HTML\NodeJs\Gulp\src\gulpfile.js:23:12)
    at bound (node:domain:421:15)"

My code:


// Importing gulp modules
let {Gulp,parallel,dest,series,src, tree} = require('gulp')

let cleanCss = require('clean-css')

let uglify = require('gulp-uglify')


let scss = require('gulp-scss')(require('scss'))

let concat = require('gulp-concat')

let autoprefixer = require('gulp-autoprefixer')

let path = require('path')

let rename = require('gulp-rename')

// Minimizing js files

function operationsWithJsFiles(){

    return src('js/*.js',[{allowEmpty:true}])
    .pipe(uglify())
    .pipe(rename({
        extname:'.min.js'
    }))
    .pipe(concat('AllJs.js'))
    .pipe(dest('../Dist'))
}



// Minimizing scss files

function operationsWithScssFiles(){

    return src('scss/*.scss')
    .pipe(scss())
    .pipe(autoprefixer({
        cascade:false
    }))
    .pipe(rename({
        extname:'.min.css'
    }))
    .pipe(concat('AllCss.css'))
    .pipe(dest('../Dist'))
}

exports.default = parallel(operationsWithJsFiles,operationsWithScssFiles)

P.s: I checked my directories properly, so, I believe, gulp has no issues with finding files P.p.s: My directory path may look confusing and hilarious xD

about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

Change this line:

return src('js/*.js',[{allowEmpty:true}])

to

return src('js/*.js',{allowEmpty:true})

You may have been confused by

src(globs, [options])

in the documentation, gulp.src signature

But the enclosing [] in the signature only indicate that that parameter is optional. The options don't actually go into the brackets. So options is just a {} object.

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda