I really don't know where I'm failing, I try 1000 ways, but I can't.
function userCheck (arr1,arr2) {
let map = {};
arr1.filter((user) => {
arr2.filter((obj) => {
if (user == obj.user) {
map[user] = obj;
}
else {
map['untracked'] = [user];
}
});
});
console.log(map)
}
userCheck([39471379, 44471379, 25471379, 35471379, 29471379,55471379],[{user: 39471379, salary: 250000}, {user: 44471379, salary: 260000}, {user: 35471379, salary: 148700},{user: 29471379, salary: 270500}]);
Create a function that receives 2 arrays, one with user numbers and the other with objects that contain data about an employee in a company (user number and salary). An object should be created where the user number is the key and the value will be the object with all the data. // In case of not finding an employee with a certain user, it means that he does not work for that company. Therefore, a new entry must be created, where the key will be “untracked” and as a value, it will have an array with all the user numbers that are not found.
expected Output:
{39471379: {ID: 39471379, salary: 250000},
44471379: {ID: 44471379, salary: 260000},
35471379: {ID: 35471379, salary: 148700},
29471379: {ID: 29471379, salary: 270500},
"untracked": [25471379,55471379]}
You could build an object of all user data and reduce the ids of the user and get the wanted data structure by checking the object.
function userCheck(users, data) {
const ids = Object.fromEntries(data.map(o => [o.user, o]));
return users.reduce((r, user) => {
if (ids[user]) r[user] = ids[user];
else r.untracked.push(user);
return r;
}, { untracked: []});
}
const
users = [39471379, 44471379, 25471379, 35471379, 29471379, 55471379],
data = [{ user: 39471379, salary: 250000 }, { user: 44471379, salary: 260000 }, { user: 35471379, salary: 148700 }, { user: 29471379, salary: 270500 }],
result = userCheck(users, data);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }Using a combination of one loop, and find.
const ids = [39471379, 44471379, 25471379, 35471379, 29471379,55471379];
const users = [{user: 39471379, salary: 250000}, {user: 44471379, salary: 260000}, {user: 35471379, salary: 148700},{user: 29471379, salary: 270500}];
function userCheck(ids, users) {
// Create two output arrays, one for the users
// that are found, the other for the untracked users
const output = [];
const untracked = [];
// Iterate over the ids array
for (const id of ids) {
// If there is a user matching that id...
const foundUser = users.find(user => {
return user.user === id;
});
// ...add the user object to the output array
if (foundUser) {
output.push({ [id]: foundUser });
// Otherwise push the id into the untracked array
} else {
untracked.push(id);
}
}
// Finally return the output array, and the
// tracked array as one merged array
return [...output, { untracked }];
}
console.log(userCheck(ids, users));Additional documentation
I have tried using a combination of forEach loop and find() method.
const ids = [39471379, 44471379, 25471379, 35471379, 29471379,55471379];
const users = [{user: 39471379, salary: 250000}, {user: 44471379, salary: 260000}, {user: 35471379, salary: 148700},{user: 29471379, salary: 270500}];
function userCheck (ids, users) {
let outputObj = {};
outputObj["untracked"] = [];
console.log(outputObj);
ids.forEach(element => {
const id = element;
const found = users.find(ele => ele.user === element);
if(found) {
outputObj[id] = {
[id] : found
}
} else {
outputObj["untracked"].push(id);
}
});
return outputObj;
const outputObj = userCheck(ids, users);
console.log(outputObj);