I have three divs and I want that every single time I click on any div, it will be swapped with a second div which is meant to be at the center.
I have tried like this and it doesn't work:
function swapDiv(event, elem) {
elem.parentNode.insertBefore(elem, elem.parentNode.secondChild);
}<div class="all-div-container">
<div class="div1" onclick="swapDiv(event,this);">
1
</div>
<div class="div2" onclick="swapDiv(event,this);">
2
</div>
<div class="div3" onclick="swapDiv(event,this);">
3
</div>
</div>1 2 3 and when I click 3 the result must be 1 3 2 from this result and I click on 1 it's must be 3 1 2
function swapDiv(event, elem) {
// get all elements in .all-div-container
const allElements = [...elem.parentElement.children];
// get index of target elem
const targetIndex = allElements.indexOf(elem);
// get center element
const centerElem = allElements[1];
// exit from function if we clicked at center elem
if (elem === centerElem) return;
// move center element
if (targetIndex === 0) {
elem.parentElement.prepend(centerElem)
} else {
elem.parentElement.append(centerElem)
}
}<div class="all-div-container">
<div class="div1" onclick="swapDiv(event,this);">
1
</div>
<div class="div2" onclick="swapDiv(event,this);">
2
</div>
<div class="div3" onclick="swapDiv(event,this);">
3
</div>
</div>Consider the following.
$(function() {
$(".all-div-container > div").click(function(event) {
if ($(this).index() == 0) {
return false;
}
var $prev = $(this).prev();
var $self = $(this).detach();
$prev.before($self);
});
});.all-div-container>div {
height: 2em;
width: 100%;
border: 1px solid #ccc;
border-radius: 3px;
margin-bottom: 3px;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="all-div-container">
<div class="div1">1</div>
<div class="div2">2</div>
<div class="div3">3</div>
</div>You did not clarify what should happen if the first item is clicked. This code will swap the clicked element and the previous element.