I have created a function wrapper to help give me various print statements:
function fnWrapper(fn, verbosity=false) {
return function(...rest) {
if (verbosity) console.log(`Calling "${fn.name}(${rest})"`)
const res = fn(...rest); // possible to add debugging **within** this wrapped function?
if (verbosity) console.log('==>', res)
return res;
}
}
function add(x,y) {
return x===0 ? y : add(x-1, y+1);
}
const add2 = fnWrapper(add, true);
add2(2,3);
// Calling "add(2,3)"
// ==> 5Is it possible to add debugging within the function itself, for example, at its most basic to translate a function such as the following:
function something(x,y) {
console.log(arguments); // add this in
...
}
So for the above function it would make the add become:
function add(x,y) {
console.log(arguments);
return x===0 ? y : add(x-1, y+1);
}
If so, how could that be done?
No, this is not possible, you cannot change what a function does.
The problem is that add calls add, and add2 also calls add only. You can however simply replace add:
function fnWrapper(fn, verbosity=false) {
return function(...rest) {
if (verbosity) console.log(`Calling "${fn.name}(${rest})"`)
const res = fn.call(this, ...rest);
if (verbosity) console.log('==>', res)
return res;
}
}
function add(x,y) {
return x===0 ? y : add(x-1, y+1);
}
add = fnWrapper(add, true); /*
^^^ */
add(2,3);