Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

243
Vistas
Generate array with values A1, A2, A3, B1, B2, B3... etc?

I'm trying to generate an array of objects where it outputs an array looking like this:

[
    {
      _id: 2,
      label: 'A1'
    },
    {
      _id: 3,
      label: 'A2'
    },
    {
      _id: 4,
      label: 'A3'
    },
    {
      _id: 5,
      label: 'B1'
    },
    {
      _id: 6,
      label: 'B2'
    },
    {
      _id: 7,
      label: 'B3'
    }
  ]

And all the way up to letter "G"... However, I cant quite to seem to wrap my head around how to generate this automatically. So far I've come up with this, but in my output it's skipping letters, and just isn't generating correctly :) Could use some help on this.

What I have so far:

function nextChar(c) {
   return String.fromCharCode(c.charCodeAt(0) + 1);
}

const supersetOptions = computed(() => {
  const maxGroup = 6;
  const maxItems = 12;
  let defaultLetter = 'a';

  return Array.from({ length: maxItems }, (value, index) => {
    const currentLetter = nextChar(defaultLetter)
    defaultLetter = nextChar(currentLetter);
    return {
      label: `${currentLetter}${index + 1}`,
      value: `${currentLetter}${index + 1}`
    };
  });
})
about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

You appear to start the _id from 2, but I've assumed this is a typo. If not, then just i+2 instead of i+1 on line 8.

You also have different property names between what you say you want, and what your code is attempting to produce. This matches what you said you wanted.

function generate(count) {
    const results = []

    for(let i = 0 ; i < count ; i++) {
        const letter = String.fromCharCode(65 + (i / 3))
        const delta = (i % 3) + 1
        results.push({
            _id: i+1,
            label: `${letter}${delta}`
        })
    }

    return results
}

console.log(generate(21))

about 4 years ago · Juan Pablo Isaza Denunciar

0

You could increment the letter after the wanted group size and check with remainder.

const
    nextChar = c => (parseInt(c, 36) + 1).toString(36),
    computed = () => {
        const
           maxPerGroup = 3,
           maxItems = 12;

        let letter = 'a';

        return Array.from({ length: maxItems }, (_, index) => {               
            const value = `${letter}${index % maxPerGroup + 1}`;
            index++;
            if (index % maxPerGroup === 0) letter = nextChar(letter);
            return { index, value };
        });
    }

console.log(computed());
.as-console-wrapper { max-height: 100% !important; top: 0; }

about 4 years ago · Juan Pablo Isaza Denunciar

0

Using generator

function* labels(end) {
  for (let i = 0; i <= end; i += 1) {
    yield {
      _id: i + 1,
      label: `${String.fromCharCode(65 + (Math.floor(i / 3) % 26))}${i % 3 + 1}`
    }
  }
}

for (const item of labels(122)) {
  console.log([item._id, item.label])
}

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda