Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

108
Vistas
I'm trying to simplify the code to a nested loop

I'm learning js and I just made a password generating code, the problem is I'm trying to simplify the code using loops inside loops, Can anyone help me understand how to do it.

function genPassword() {
  let chars = "0123456789abcdefghijklmnopqrstuvwxyz!@#$%^&*()ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  var passwordLength = 12;
  var password1 = "";
  var password2 = "";
  var password3 = "";
  var password4 = "";
  for (var i = 0; i <= passwordLength; i++) {
    var randomNumber1 = Math.floor(Math.random() * chars.length);
    var randomNumber2 = Math.floor(Math.random() * chars.length);
    var randomNumber3 = Math.floor(Math.random() * chars.length);
    var randomNumber4 = Math.floor(Math.random() * chars.length);
    password1 += chars.substring(randomNumber1, randomNumber1 + 1);
    password2 += chars.substring(randomNumber2, randomNumber2 + 1);
    password3 += chars.substring(randomNumber3, randomNumber3 + 1);
    password4 += chars.substring(randomNumber4, randomNumber4 + 1);
  }
  document.getElementById("password-1").textContent = password1;
  document.getElementById("password-2").textContent = password2;
  document.getElementById("password-3").textContent = password3;
  document.getElementById("password-4").textContent = password4;
}

genPassword()
<div id="password-1"></div>
<div id="password-2"></div>
<div id="password-3"></div>
<div id="password-4"></div>

about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

Just wrap the code for creating and displaying the password in another for loop. Make sure to change the number of iterations to match your project.

function genPassword() {
    let chars = "0123456789abcdefghijklmnopqrstuvwxyz!@#$%^&*()ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    let passwordLength = 12;
    
    for (let j = 1; j <= 4; j++) {
        
        let password = "";
        for (let i = 0; i <= passwordLength; i++) {
            let randomNumber = Math.floor(Math.random() * chars.length);
            password += chars.substring(randomNumber, randomNumber + 1);
        }
        document.getElementById("password-" + j).textContent = password;
    }
}
<span id="password-1"></span><br />
<span id="password-2"></span><br />
<span id="password-3"></span><br />
<span id="password-4"></span><br />

<button onclick="genPassword()">Click</button>

about 4 years ago · Juan Pablo Isaza Denunciar

0

Let's consider how you might do this without explicit loops.

You can generate an array of arbitratry length (len) as follows:

[...new Array(len)]

You can then map the items in this array with Array.prototype.map. We don't actually care about the default values in the array, so we can just discard that value and map it to a random character. It isn't necessary to use substring... a string can be indexed like an array (i.e. chars[n])... so...

[...new Array(len)].map(() => chars[Math.floor(Math.random() * chars.length)])

will give you back an array where each index contains a randomly selected character.

So now, all we have to do is join them back up again to form a string. Array.prototype.join does this for us:

[...new Array(len)]
    .map(() => chars[Math.floor(Math.random() * chars.length)])
    .join("")

Let's pop all of this into a function:

function generatePassword(length){
  return [...new Array(len)]
      .map(() => chars[Math.floor(Math.random() * chars.length)])
      .join("")
}

Calling generatePassword(12) will hand back a 12 char password.

Now, let's generate 4 of them using the same trick as above

const passwords = [...new Array(4)].map(() => generatePassword(passwordLength))

then let's output them:

passwords.forEach((password, index) => {
    document.getElementById("password-" + (index + 1)).textContent = password;
})

Putting it all together:

const chars = "0123456789abcdefghijklmnopqrstuvwxyz" + 
              "!@#$%^&*()ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const passwordLength = 12;

function generatePassword(length) {
  return [...new Array(length)]
    .map(() => chars[Math.floor(Math.random() * chars.length)])
    .join("");
}

const passwords = [...new Array(4)].map(() => generatePassword(passwordLength));

passwords.forEach((password, index) => {
  document.getElementById("password-" + (index + 1)).textContent = password;
})
<div id="password-1"></div>
<div id="password-2"></div>
<div id="password-3"></div>
<div id="password-4"></div>

about 4 years ago · Juan Pablo Isaza Denunciar

0

function genPassword() {
  let chars = "0123456789abcdefghijklmnopqrstuvwxyz!@#$%^&*()ABCDEFGHIJKLMNOPQRSTUVWXYZ";

let passwordArray = [
     { elemIdName: 'password-1', elemIdValue: ''},
     { elemIdName: 'password-2', elemIdValue: ''},
     { elemIdName: 'password-3', elemIdValue: ''},
     { elemIdName: 'password-4', elemIdValue: ''},
  ]
  let passwordLength = 12;

  for (var i = 0; i <= passwordLength; i++) {
    passwordArray.forEach((password) => {
      let randomNumber1 = Math.floor(Math.random() * chars.length);
      password.elemIdValue += chars.substring(randomNumber1, randomNumber1 + 1);
    })
  }
  passwordArray.forEach((password) => {
     document.getElementById(password.elemIdName).textContent = password.elemIdValue;
  })
}

genPassword()
<div id="password-1"></div>
<div id="password-2"></div>
<div id="password-3"></div>
<div id="password-4"></div>

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda