Trying to create a function that checks a password for integers and then return an object which will store a boolean representing whether the password contains an integer, and then destructure the boolean out of the function, but I keep getting this problem...
function checkForInteger(password) {
const arrayOfIntegers = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"];
let intBoolean = {};
arrayOfIntegers.forEach((int) => {
if (password.includes(int)) {
intBoolean = { integerIsPresent: password.includes(int) };
} else {
intBoolean = { integerIsPresent: password.includes(int) };
}
});
return intBoolean;
}
checkForInteger("3gufr"); //returns {integerIsPresent:false}You're replacing intBoolean each time through the loop. So if 3 is found, you'll set it to {integerIsPresent: true} on that iteration, but then replace it with {integerIsPresent:false} on the remaining iterations.
Initialize it to false before the loop, and only set it to true when you get a match.
function checkForInteger(password) {
const arrayOfIntegers = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"];
let intBoolean = {
integerIsPresent: false
};
arrayOfIntegers.forEach((int) => {
if (password.includes(int)) {
intBoolean.integerIsPresent = true;
}
});
return intBoolean;
}
console.log(checkForInteger("3gufr"));You can also simplify it by using Array.some()
function checkForInteger(password) {
const arrayOfIntegers = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"];
let intBoolean = {
integerIsPresent: arrayOfIntegers.some(int => password.includes(int))
};
return intBoolean;
}
console.log(checkForInteger("3gufr"));or you can use a regular expression.
function checkForInteger(password) {
return {
integerIsPresent: !!password.match(/\d/)
};
}
console.log(checkForInteger("3gufr"));password.match() returns an array when there's a match. !! converts that to a boolean.You could probably adjust your logic a little. forEach doesn't allow to you break out of the loop - for/of does.
Loop over the array. If there is a match return the object containing the match, otherwise return an object with a false value.
const arrayOfIntegers = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'];
function checkForInteger(password) {
for (const el of arrayOfIntegers) {
if (password.includes(el)) {
return { integerIsPresent: true };
}
}
return { integerIsPresent: false };
}
console.log(checkForInteger('3gufr'));
console.log(checkForInteger('nnh5dd'));
console.log(checkForInteger('abcdef'));this is how I resolved the issue though, thanks a lot @Barmar
function checkForInteger(password) {
const arrayOfIntegers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9];
const checkPassword = (el) => password.includes(el);
const integerIsPresent = arrayOfIntegers.some(checkPassword);
// console.log(integerIsPresent);
return integerIsPresent;
}