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Creating an array of objects from arrays of nested objects

I'm trying to create an array of objects from an array of objects in which has nested arrays. The nested arrays are going to be subsituted for the key name followed by a dot:
for example:

const data = [ id: 5, name: "Something", obj: { lower: True, higher: False } ]
result = ["id", "name", "obj.lower", "obj.higher"]

I could manage to key the nested keys and values, but I can't seem to get the objs from the array.
For example (expected result):

const data = [ id: 5, name: "Something", obj: { lower: True, higher: False } ]
const newData = [{id: 5}, {name: "Something"}, {obj.lower: True}, {obj.higher: False}]

I have attempted:

 getValues = object => Object.entries(object).flatMap(([k, v]) => {
    if (typeof v !== "object") {
      return {[k]: v}
    }
    return v && typeof v === 'object' ? this.getKeys(v).map(s => `${k}.${s}`) : [k];
  });

I will be comparing these filtered array of objects with a user data that seems like this:

export const requiredKeys = {
  data: {
    id: null,
    status: null,
    summary: null,
    // "updated_by.id": null,
    // "updated_by.firstname": null,
    // "updated_by.lastname": null,
    // "updated_by.username": null,
    // "updated_by.blocked": null,
    // "pillars.pillarsType": null,
    // "student.created_by": null,
    // state: null,
about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

You could map the key/values or the pairs of the nested objects. From this entries get a new objects.

const
    getEntries = object => Object
        .entries(object)
        .flatMap(([k, v]) => v && typeof v === 'object'
            ? getEntries(v).map(([l, v]) => [`${k}.${l}`, v])
            : [[k, v]]
        ),
    data = { id: 1, item: "Item 001", obj: { name: 'Nilton001', message: "Free001", obj2: { test: "test001" } } },
    result = getEntries(data).map(pair => Object.fromEntries([pair]));

console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
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