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How can I format a number adding corresponding suffix to the end of it? - Java

I need in my text view to add a number, but also I need to add the corresponding suffix to that number like 1 is 1st, 2 is 2nd and so on. Is there any way to do this instead of writing a bunch of switch statements? The number is dynamic, so it doesn't have a range. Thank you.

Detailed description:

public String getNumberWithSuffix(int number) {
    /** Add an suffix to the end of the number, convert to string and return. 
        E.g. the number is 1, the suffix needs to be 'st', 
        so we concat them and return 1st. 
        If the number is 2, the suffix needs to be 'nd', 
        we concat them and return 2nd. 
        The range is not specified so it can be any integer number. 
    **/
}
over 4 years ago · Santiago Trujillo
2 Respuestas
Responde la pregunta

0

Something like this -

// Initialize this as a singelton smwhere.
Map<Integer, String> suffixMapper = new HashMap<Integer, String>
suffixMapper.put(1, 'st');
suffixMapper.put(2, 'nd');
suffixMapper.put(3, 'rd');
String getSuffix(int num) {
  if (num % 100 / 10 == 1) return "th"
  Integer lastDigit = num % 10
  String suffix = suffixMapper.get(lastDigit) != null ? suffixMapper.get(lastDigit) : "th";
  return suffix;
}

You can also make the map return an Optional to handle the null if needed.

If you are using Android, you can check this answer out - https://stackoverflow.com/a/49384322/4983469

over 4 years ago · Santiago Trujillo Denunciar

0

Found an answer from similar question:-

public static String ordinal(int i) {
    String[] suffixes = new String[] { "th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th" };
    switch (i % 100) {
    case 11:
    case 12:
    case 13:
        return i + "th";
    default:
        return i + suffixes[i % 10];

    }
}

Link - https://stackoverflow.com/a/6810409/8762338

over 4 years ago · Santiago Trujillo Denunciar
Responde la pregunta
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