I'm really trying to understand RegEx and I feel like this issue should be easy and straightforward, but for some reason I'm really struggling to get exactly what I need. I've looked through at least 20 articles here and none of them are getting me there.
What I need is to capture all words after a lookbehind so I can count them. Here's what I've got so far:
RegEx: /(?<=\> )(\w*)/gi
String: "Mon Jan 11 11:00 <ralph> Hello all!!"
Capture all words after "> ", so in the above I only want the capture group to individually capture "Hello" and "all", so I can count the group and get the number words after the username, "<ralph>" in this example.
The above RegEx is just what I'm currently working with and it of course is only capturing the first word. I've also tried putting * and + after the capture group, but that nullifies the capture group for some reason.
I've also tried (?<=\> )((\w*)(?:\W+))*, and while this does match everything after the lookbehind, it only captures "all!!" and "all" in the 2 different captures. I'm not sure why "!!" is returning in any capture as I have it to match only with (?:).
For example
const str = "Mon Jan 11 11:00 <ralph> Hello all. How are you?";
console.log( str.match(/(?<=\> (?:\w+\W+)*)\w+/g) );I'm not sure why "!!" is returning in any capture as I have it to match only with (?:).
Yes, but it is also captured by the first capture group. For example, if "x" is matched by ((?:x)), then the first capture group will contain "x" even though it is also inside the second group which is non-capturing.
(?<=\> )(.+) works fine for me it captures Hello all!! from Mon Jan 11 11:00 <ralph> Hello all!!
Is it what you need?
Is there a regular pattern after the > or it's random?
Anyway, this (?<=\> )(.*) matches your example.