Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

157
Vistas
How to group by with sum in javascript using the reduce method

I have the following array:

let array = [
  { date: '2022-06-29', cost: 3.874886 },
  { date: '2022-06-28', cost: 3.357631 },
  { date: '2022-06-28', cost: 92.24 },
  { date: '2022-06-28', cost: 221.47 },
  { date: '2022-06-28', cost: 164.8 },
  { date: '2022-06-29', cost: 263.58 },
  { date: '2022-06-29', cost: 30.19 },
  { date: '2022-06-29', cost: 3.72 }, 
  { date: '2022-11-29', cost: 33.19 },
  { date: '2022-11-01', cost: 31.72 }
]

I'm trying to use the .reduce method to get the sum of cost, grouped by date, which would look like this:

[
  {date: '2022-06-28', cost: 481.867631},
  {date: '2022-06-28', cost: 301.364886},
  {date: '2022-11-01', cost: 31.72},
  {date: '2022-11-29', cost: 33.19}
]
about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

you can do something like this

const group = data => Object.values(data.reduce((res, {date, cost}) => {
   return {
     ...res,
     [date]: {date, cost: (res[date] || {cost:0}).cost + cost}
   }

}, {}))


const data = [
  { date: '2022-06-29', cost: 3.874886 },
  { date: '2022-06-28', cost: 3.357631 },
  { date: '2022-06-28', cost: 92.24 },
  { date: '2022-06-28', cost: 221.47 },
  { date: '2022-06-28', cost: 164.8 },
  { date: '2022-06-29', cost: 263.58 },
  { date: '2022-06-29', cost: 30.19 },
  { date: '2022-06-29', cost: 3.72 }, 
  { date: '2022-11-29', cost: 33.19 },
  { date: '2022-11-01', cost: 31.72 }
]

console.log(group(data))

about 4 years ago · Juan Pablo Isaza Denunciar

0

let array = [
  { date: '2022-06-29', cost: 3.874886 },
  { date: '2022-06-28', cost: 3.357631 },
  { date: '2022-06-28', cost: 92.24 },
  { date: '2022-06-28', cost: 221.47 },
  { date: '2022-06-28', cost: 164.8 },
  { date: '2022-06-29', cost: 263.58 },
  { date: '2022-06-29', cost: 30.19 },
  { date: '2022-06-29', cost: 3.72 }, 
  { date: '2022-11-29', cost: 33.19 },
  { date: '2022-11-01', cost: 31.72 }
]




const result = array.reduce((acc, item) => {
  const itemIndex = acc.findIndex(i => i.date === item.date);
  if (itemIndex !== -1) {
    acc[itemIndex].cost += item.cost
  } else {
   acc.push(item)
  }
  return acc;
}, [])

console.log(result)
[
  {date: '2022-06-28', cost: 481.867631},
  {date: '2022-06-28', cost: 301.364886},
  {date: '2022-11-01', cost: 31.72},
  {date: '2022-11-29', cost: 33.19}
]

about 4 years ago · Juan Pablo Isaza Denunciar

0

here is my way to achieve your desire output.

let array = [
  { date: '2022-06-29', cost: 3.874886 },
  { date: '2022-06-28', cost: 3.357631 },
  { date: '2022-06-28', cost: 92.24 },
  { date: '2022-06-28', cost: 221.47 },
  { date: '2022-06-28', cost: 164.8 },
  { date: '2022-06-29', cost: 263.58 },
  { date: '2022-06-29', cost: 30.19 },
  { date: '2022-06-29', cost: 3.72 }, 
  { date: '2022-11-29', cost: 33.19 },
  { date: '2022-11-01', cost: 31.72 }
]

const newArray = array.reduce((prev, curr) => {
  const check = prev.findIndex(f => f.date === curr.date);
  if (check > -1) {
    prev[check].cost += curr.cost
  } else {
    prev.push(curr)
  }
  return prev;
}, []);

console.log(newArray)

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda