!I'm a beginner in js! is there any way to let the return wait for both for loops to finish I tried all the solutions here " https://stackoverflow.com/questions/27914209/how-could-i-run-a-function-after-the-completion-of-a-for-loop-in-node-js" but no one of them works I think because is nested loop
function StatisticsPerGameId (IDs){
console.log(IDs)
let doubldoubl={};
for (let i=0; i <IDs.length;i++){
const options = {
method: 'GET',
url: 'https://api-nba-v1.p.rapidapi.com/players/statistics',
params: {game: IDs[i]},
headers: {
'X-RapidAPI-Host': 'api-nba-v1.p.rapidapi.com',
'X-RapidAPI-Key': 'afgsdgbsdghbrynhndf6hn6dfhndfhn61dhddfhn'
}
};
axios.request(options).then(function (response) {
console.log(response.data.response[0].points)
for(let j in response.data.response){
let dd = 0;
if( response.data.response[j].points >= 10){dd=dd+1;};
if( response.data.response[j].totReb >= 10){dd=dd+1;};
if(dd == 2 ){
doubldoubl=doubldoubl+{
name:response.data.response[j].player.firstname +" "+ response.data.response[j].player.lastname,
teamOfplayer : response.data.response[j].team.name,
teamOfplayerlogo:response.data.response[j].team.logo,
}
};
dd = 0 ;
}
}).catch(function (error) {
console.error(error);
});
}
return doubldoubl;
}
axios.request() returns a promise, which will resolve asynchronously when the request is fetched. Calling .then(function () {...}) will call that function when the request is ready.
The best way to wait for all the requests is to pass them all into Promise.all():
function StatisticsPerGameId (IDs){
...
const promises = []
for (let i=0; i <IDs.length;i++){
...
const promise = axios.request(...).then(function (response) {...}).catch(function (error) {...});
promises.push(promise)
}
return Promise.all(promises).then(function () {
return doubldoubl;
});
}
Note that this will make StatisticsPerGameId return a promise for the result, which will similarly need to be waited on asynchronously.
See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Using_promises#composition