I was solving a codewars challenge and got stuck in an endless loop. The task is to find from a given input like year 1987 the next greater integer that has only distinct digits. In that case it would be 2013 as 1988, 1998,2000 etc. do not have 4 distinct digits. I wanted to solve this task with an Object and see where the length of the Object.keys(obj) is equal to 4.
Here is my try
function distinctDigitYear(year) {
let obj = {}
let count = 1
let yearCounter = year + count
while (Object.keys(obj).length !==4) {
obj = {}
yearCounter.toString().split('').forEach(el=> {
if(!Object.keys(obj).includes(el)){
obj[el] = 1
} else {
obj[el] +=1
}
}
)
count++
}
return yearCounter + 1
}
distinctDigitYear(2000)Thanks for reading!
Details are commented in eample below
// Pass a 4 digit year -- 1987
function distinctDigitYear(year) {
++year; // Increment -- 1988
/*
Convert year number into a String. Spread the String into 4
separate characters with the spread operator ... then convert an
Array into a Set eliminates any duplicates, then convert it back to an Array.
*/
let yyyy = [...new Set([...year.toString()])];
// If there are no dupes, yyyy will be 4 characters
if (yyyy.length === 4) {
/*
join() the array into a String and return it
*/
return yyyy.join('');
}
/*
If the lenght of yyyy is less than 4
recursively call dDY() passing next year through.
*/
return distinctDigitYear(year);
};
console.log(distinctDigitYear(1987));
console.log(distinctDigitYear(2020));
console.log(distinctDigitYear(1910));