I have string s and need to check if that string contains every single alphabet from a to z. What will the regex be to check this condition? where s can be very big string with multiple words separated with space.
ex:
pattern.test("zy aemnofgbc jkhil pqasdfrs tuvrhfwx")
should return true as it contains all a-z alphabets at least ones.
pattern.test("sdfasbcd effsdgh ijsfghtkl mnhtop qrsjht uvwmnmx yfdhjkd")
should return false as it doesn't have alphabet z.
Looking for optimum solution.
the easiest way is by extracting unique chars
function testAlphabet(str) {
var chars = str.replace(/[^a-z]/g).split(''); // it may need to convert to lowercase
// remove duplicate
chars = [...new Set(chars)];
console.log(chars.join('').length == 26)
}
testAlphabet("zy aemnofgbc jkhil pqasdfrs tuvrhfwx")
testAlphabet("sdfasbcd effsdgh ijsfghtkl mnhtop qrsjht uvwmnmx yfdhjkd")First solution with regex - removes all non-alphabetic characters, duplicates, and compares the string length with 26.
Second solution without regex, just checks is every alphabetic characters in string.
const test1 = (str) => str.replace(/[^a-z]|(.)(?=.*\1)/gi, '').length === 26;
const test2 = (str) => [...`abcdefghijklmnopqrstuvwxyz`]
.every(ch => str.includes(ch));
console.log(test1('zy aemnofgbc jkhil pqasdfrs tuvrhfwx'));
console.log(test1('y aemnofgbc jkhil pqasdfrs tuvrhfwx'));
console.log(test2('zy aemnofgbc jkhil pqasdfrs tuvrhfwx'));
console.log(test2('y aemnofgbc jkhil pqasdfrs tuvrhfwx'));.as-console-wrapper{min-height: 100%!important; top: 0}function isAllaz() {
let s = "zy aemnofgbc jkhil pqasdfrs tuvrhfwx";
//console.log([...new Set(s.split("").filter(e => e.match(/[a-z]/)))].length==26);
return [...new Set(s.split("").filter(e => e.match(/[a-z]/)))].length==26;
}