I'm currently working on a login portal.
I already set the log in and log out functions and placed a session start button on every page.
My problem now is that I would like to update the user image based on the identity of who is logged in.
I'm using a template my boss chose, and this is the code where the image is:
<span>
<img src="../../global/portraits/5.jpg" alt="...">
</span>
Just a simple <img> tag with the link where the image is.
My project is in an html file with php implemented, and I tried to do this in the <span> tag, instead of <img>:
<?php
$W = ["Raffaella", "Milena", "Domiziana"];
$M = ["Umberto", "Domenico"];
if ($_SESSION["nome"] == $W) {
echo '<img src="W.jpg">';
} else if ($_SESSION["nome"] == $M){
echo '<img src="M.jpg">';
}
?>
where $_SESSION["nome"] represents the current user logged in. However, it doesn't do anything, not even producing an error.
Can someone explain how I can do it correctly, please? I'm new to php and trying to understand by studying alone on the internet
I was also considering JavaScript for this work (instead of PHP), but I don't know where to start
It looks like both $W and $M are array of names, rather than a single user, if that's the case, I assume you're trying to determine if a user is in that array. In PHP, you can use:
in_array($_SESSION["nome"], $W)
https://www.php.net/manual/en/function.in-array.php
which will return true/false.
if (true === in_array($_SESSION["nome"], $W)) {
echo '<img src="W.jpg">';
} else if (true === in_array($_SESSION["nome"], $M){
echo '<img src="M.jpg">';
}
But, this only gives two separate images for up to 5 unique names, and I'm not sure if that's what you're going for.