i want to get all strings between brackets [].
i tried regex match methode and it's not working
i only get the first element changed
here is my code
tags = "[r,a,9]@[r,a,8].com".match(/([(?:[??[^[]*?]))/);
for (let index = 0; index < tagNumber; index++) {
console.log(tags[index]);
fromName = "[r,a,9]@[r,a,8].com".replace(tags[index], "haha");
}/\[.+?\]/g
/ denotes the start of the pattern
\[ matches the [ character
.+? matches any character, 1 or more times, lazily
\] matches the ] character
/g denotes the end of the pattern and to find ALL matches
const input = "[r,a,9]@[r,a,8].com"
const pattern = /\[.+?\]/g
const tags = Array.from(input.match(pattern))
console.log(tags)
const fromName = input.replace(pattern, "haha")
console.log(fromName)You need to escape [ and ] to match them literally. There's no need for the capture group around everything.
Add the g modifier to match all the occurrences in the string.
tags = "[r,a,9]@[r,a,8].com".match(/\[[^[]*?\]/g);
let tagNumber = tags.length;
for (let index = 0; index < tagNumber; index++) {
console.log(tags[index]);
fromName = "[r,a,9]@[r,a,8].com".replace(tags[index], "haha");
console.log(fromName)
}You can use a regular expression in replace() to replace all the matches at once.
fromName = "[r,a,9]@[r,a,8].com".replace(/\[[^[]*?\]/g, "haha");
console.log(fromName)