Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

176
Vistas
How to create two objects from one object if fields are not same in object?

I have below array of objects and I have to create a new array of objects based on the below conditions

  1. if id is not empty and registration id is empty push this object into the result array.

  2. if registration id is not empty and id is empty then assign registration id to id and push this object into the result array.

  3. if id is not empty and registration id is not empty then

    a.check id and registration id are the same then assign registration id to id push this object into the result array.

    b. id and registration id are not same create two object .one with "id": 1 and another one with assign registration id to id("id": 100)

var userData =[{
"id": 1,
"name": "abcd",
"place":"xyz",
"registrationid": 100


}];

var result = [];

userData.forEach( (element) => {
   if(element.id !="" && element.registrationid ==""){
        console.log("1");
        result.push(element);
        
   } else if(element.registrationid !="" && element.id ==""){
        console.log("2");
        element.id  = element.registrationid;
        result.push(element);
        
   } else if(element.registrationid !="" && element.id !=""){
             console.log("3");
          if(element.id  == element.registrationid){
          console.log("4");
            element.id  = element.registrationid;
              result.push(element);
            
        }else if(element.id  != element.registrationid){
          console.log("5");
          result.push(element)
          element.id  = element.registrationid;
            result.push(element)
        }
        
   }
});

console.log(result)

Expected output result array should return

[
{
"id": 1,
"name": "abcd",
"place":"xyz",
"registrationid": 100
},
{
"id": 100,
"name": "abcd",
"place":"xyz",
"registrationid": 100
},

];

Gone through this but could not get any idea please help me out guys

about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

Create a copy in step 3b:

var userData = [{
  "id": 1,
  "name": "abcd",
  "place": "xyz",
  "registrationid": 100
}];

var result = [];

userData.forEach((element) => {
  if (element.id != "" && element.registrationid == "") {
    console.log("1");
    result.push(element);
  } else if (element.registrationid != "" && element.id == "") {
    console.log("2");
    element.id = element.registrationid;
    result.push(element);
  } else if (element.registrationid != "" && element.id != "") {
    console.log("3");
    if (element.id == element.registrationid) {
      console.log("4");
      result.push(element);
    } else if (element.id != element.registrationid) {
      console.log("5");
      result.push({
        ...element
      })
      element.id = element.registrationid;
      result.push(element)
    }
  }
});

console.log(result)

The assignment in 3a doesn't make sense. I removed it. I prefer flatMap

var userData = [{
  "id": 1,
  "name": "abcd",
  "place": "xyz",
  "registrationid": 100
}];

var result = userData.flatMap((element) => {
  if (element.id != "" && element.registrationid == "") {
    console.log("1");
    return element;
  } else if (element.registrationid != "" && element.id == "") {
    console.log("2");
    element.id = element.registrationid;
    return element;
  } else if (element.registrationid != "" && element.id != "") {
    console.log("3");
    if (element.id == element.registrationid) {
      console.log("4");
      return element;
    } else if (element.id != element.registrationid) {
      console.log("5");
      const oldId = element.id;
      element.id = element.registrationid;
      return [{
        ...element, id: oldId
      }, element];
    }
  }
});

console.log(result)

about 4 years ago · Juan Pablo Isaza Denunciar

0

Please try the following

  const userData = [{
    "id": 1,
    "name": "abcd",
    "place": "xyz",
    "registrationid": 100
  }];
  const result = [];

  userData.forEach((data) => {
    if (data.id && !data.registrationid) {
      result.push(data);
    }

    if (!data.id && data.registrationid) {
      const output = {
        ...data,
        id: data.registrationid
      }

      result.push(output)
    }
    
    if (data.id && data.registrationid) {
      if (data.id === data.registrationid) {
        result.push(data);
      } else {
        const obj1 = {...data, id: 1};
        const obj2 = {...data, id: 100}
        
        result.push(obj1, obj2)
      }
    }
  });
  
  console.log(result);

about 4 years ago · Juan Pablo Isaza Denunciar

0

You could create new object if you wanna do this business

var userData = [
  {
    id: 1,
    name: "abcd",
    place: "xyz",
    registrationid: 100,
  },
];

var result = [];

userData.forEach((element) => {
  let newEl;
  if (element.id != "" && element.registrationid == "") {
    newEl = { ...element };
    result.push(newEl);
  } else if (element.registrationid != "" && element.id == "") {
    newEl = { ...element, id: element.registrationid };
    result.push(newEl);
  } else if (element.registrationid != "" && element.id != "") {
    result.push(element);
    if (element.id != element.registrationid) {
      newEl = { ...element, id: element.registrationid };
      result.push(newEl);
    }
  }
});

console.log(result);
about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda