i want to ask about array.sort() was looking for solution about this kind of problem how to sort a array with this kind of structure
array.sort((a, b) => a.foo.foo1.foo2 - b.foo.foo1.foo2)
where this working but after rewrite the code for multiple use case
export const handleSort = (arr, sortBy, desc) => {
arr = [...arr];
if (desc) {
return arr.sort((a, b) => b[sortBy] - a[sortBy]);
} else {
return arr.sort((a, b) => a[sortBy] - b[sortBy]);
}
later on if i need like
return arr.sort((a, b) => b[sortBy][0][1] - a[sortBy][0][1]);
i cant use this
You could use a function and an array for getting the right property.
const
getValue = (object, keys) => keys?.length
? keys.reduce((o, k) => o[k], object)
: object,
ASC = (a, b) => a - b,
DESC = (a, b) => b - a,
sortBy = (order, keys) => (a, b) => order(getValue(a, keys), getValue(b, keys)),
keys = ['foo', 'foo1', 'foo2'],
data = [{ foo: { foo1: { foo2: 7 } } }, { foo: { foo1: { foo2: 2 } } }, { foo: { foo1: { foo2: 9 } } }, { foo: { foo1: { foo2: 6 } } }, { foo: { foo1: { foo2: 1 } } }, { foo: { foo1: { foo2: 4 } } }];
// usage
data.sort(sortBy(ASC, keys));
console.log(data);.as-console-wrapper { max-height: 100% !important; top: 0; }Maybe a good idea is to define function that will handle getting properties for the compare purpose?
const handleSort = (arr, desc, getValue) => {
if (desc) {
return arr.sort((a,b) => getValue(a) - getValue(b));
}
return arr.sort((a,b) => getValue(b) - getValue(a));
}
In this way, you can use upper function like:
return handleSort(myArray, true, (obj) => obj.foo.foo1.foo2);