I'm trying to use a function with a parameter of namedTuple which has default values. I tried this. Is that somehow possible?
from typing import Optional, NamedTuple
Stats = NamedTuple("Stats", [("min", Optional[int]), ("max", Optional[int])])
def print(value1: Stats=None, value2: Stats=None):
print("min: ", value1.min)
print("max: ", value1.max)
print()
Rename your print() function, first you're using the built-in function name print which is bad style, secondly then you make a recursive call to print() inside print() (and I'm sure you meant to call the actual built-in print() inside function's body).
Second, use collection.namedtuple class to implement actual type of tuple, like following:
Also type annotations are not needed.
from collections import namedtuple
StatsTup = namedtuple('Stats', ['min', 'max'], defaults = [3, 7])
def printf(value1 = StatsTup(), value2 = StatsTup(max = 10)):
print("min1: ", value1.min)
print("max1: ", value1.max)
print("min2: ", value2.min)
print("max2: ", value2.max)
printf()
printf(StatsTup(12, 14), StatsTup(16, 18))
Output:
min1: 3
max1: 7
min2: 3
max2: 10
min1: 12
max1: 14
min2: 16
max2: 18
As you can see in code and output above I'm passing named tuple as default parameters to funcion. You can omit tuple's fields values if you provide defaults = [...] like I did. If you provide such defaults then you may provide no values to tuple like StatsTup() or some values like StatsTup(max = 123) or all values like StatsTup(min = 20, max = 35).
Solution above works only starting with Python 3.7, for older versions of Python do following:
from collections import namedtuple
StatsTup = namedtuple('Stats', 'min max')
StatsTup.__new__.__defaults__ = (3, 7)
def printf(value1 = StatsTup(), value2 = StatsTup(max = 10)):
print("min1: ", value1.min)
print("max1: ", value1.max)
print("min2: ", value2.min)
print("max2: ", value2.max)
printf()
printf(StatsTup(12, 14), StatsTup(16, 18))