I tested this code and the result I expected was getting the Chicken log first, but I was wrong, everytime I run this code I get the Egg log first, does anybody knows whats going on here?
setTimeout(() => {
console.log("Egg");
}, 1);
setTimeout(() => {
console.log("Chicken");
}, 0);Edit: Notice that this behaves differently if those delays are 101ms and 100ms respectively, so the behavior changes even if the difference on the timer is still 1ms
The time is in milliseconds that the timer should wait before the specified function or code is executed. 1000ms will be 1 sec and since your input to a parameter was 1ms JS just displayed it in the order it was written because 1ms and 0ms were comparable. Moreover, you can use async-await to wait for tasks that would take longer. For instance,
function timeout(ms) {
return new Promise(resolve => setTimeout(resolve, ms));
}
async function printOnTime() {{
console.log("Chicken")
await timeout(1000);
console.log("Egg")
}}
printOnTime();
In this example, Chicken will be printed asap however in order to print Egg it will wait for 1 sec (1000ms) and finally print Egg.