Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

183
Vistas
Regex to match characters after the last colon that is not within curly brackets

I need a regex that matches (and lists) all 'modifiers' of a string. Modifiers are individual letters behind the last : in the string. Modifiers can have variables which would be written in curly brackets, e.g. a{variable}. Variables may contain the character : -- which makes it a bit tricky, because we must look for the last : that is NOT between { and }. This is currently my biggest problem, see Example 6 below.

(If it matters, the target language for this will be javascript.)

I got this working already for the most cases, but got a few edge cases that I can not get to work.

My regex so far is:

/(?!.*:)([a-z](\{.*?\})*)/g

Example 1: Single modifier

something:a should match a - working fine

Example 2: Multiple modifiers

something:abc should match a, b, and c - working fine

Example 3: Single modifier with variable

something:a{something} should match a{something} - working fine

Example 4: Single modifier with multiple variables

something:a{something}{something} should match a{something}{something} - working fine

Example 5: Multiple modifiers with variables

something:ab{something}cd{something}{something}efg should match a, b{something}, c, d{something}{something}, e, f, g - working fine

Example 6: Variable containing :

something:a{something:2} - should match a{something:2} - does NOT work. I probably need to modify the negative lookahead somehow to ignore colons in curly brackets, but I couldn't find out how to do that.

Example 7: String not containing a :

something - should match nothing, but matches each letter individually. This may or may not be easy to fix, but my brain currently can't work this out.

Here is a link to test / play around with this regex and the examples: https://regexr.com/6h4h0

If anyone can help me to figure out how to make the regex work for example 6 and 7, I'd be very grateful!

about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

You can use

const regex = /.*:((?:[a-zA-Z](?:{[^{}]*})*)+)$/;
const extract_rx = /[a-zA-Z](?:{[^{}]*})*/g;
const texts = ['something:a','something:abc','something:a{something}','something:a{something}{something}','something:ab{something}cd{something}{something}efg','something:a{something:2}','something:a{something:2}b{something:3}','something'];
for (const text of texts) {
  const m = text.match(regex);
  if (m) {
    const matches = m[1].match(extract_rx);
    console.log(text, '=>', matches);
  } else {
    console.log(text, '=> NO MATCH'); 
  }
}

See the main regex demo. Details:

  • .*: - matches any zero or more chars other than line break chars as many as possible and then a : followed with...
  • ((?:[a-zA-Z](?:{[^{}]*})*)+) - Group 1: one or more sequences of
    • [a-zA-Z] - an ASCII letter
    • (?:{[^{}]*})* - zero or more sequences of a {, zero or more chars other than { and } and then a } char
  • $ - end of string.

Once there is a match, Group 1 is parsed again to extract all sequences of a letter and then any zero or more {...} substrings right after from it.

about 4 years ago · Juan Pablo Isaza Denunciar

0

What you could do instead is make sure there is a colon somewhere before the matched string with a positive lookbehind.
Essentially switching (?!.*:) for (?<=:.*).

Playground

const regex = /(?<=:.*)([a-z](\{.*?\})*)/g;

const strings = [
  "something:a",
  "something:abc",
  "something:a{something}",
  "something:a{something}{something}",
  "something:ab{something}cd{something}{something}efg",
  "something:a{something:2}",
  "something",
];

for (const string of strings) {
  console.log(string.match(regex));
}

about 4 years ago · Juan Pablo Isaza Denunciar

0

Not sure if this is what you want:

:([a-z\{.*?\}0-9])*

I would try longer, but have to go catch a flight.

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda