Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

226
Vistas
Removing trailing zeros from number if it is an integer

So I am learning javascript, and I have not been working with it for very long, and I have the following code:

function doslope() {
  var b, m;
  x1 = parseFloat(document.getElementById("x1").value);
  y1 = parseFloat(document.getElementById("y1").value);
  x2 = parseFloat(document.getElementById("x2").value);
  y2 = parseFloat(document.getElementById("y2").value);
  m = (y2 - y1) / (x2 - x1);
  b = y1 - m * x1;
  m = m.toFixed(2);
  b = b.toFixed(2);

  if (Number.isInteger(m)) {
    m = parseInt(m.toString());
  }

  if (Number.isInteger(b)) {
    b = parseInt(b.toString());
  }

  document.getElementById("result").innerHTML = "y=" + m + "x+" + b;
}
<label>x1<input id="x1" /></label><br>
<label>y1<input id="y1" /></label><br>
<label>x2<input id="x2" /></label><br>
<label>y2<input id="y2" /></label><br>
<button onclick="doslope()">Do slope</button><br>
<br>
<output id="result"></output>

When I run this with the numbers x1=5, y1=5, x2=6, and y2=3 I get the result y=-2.00x+15.00.

I am wondering what error I am making here that it is not removing the .00 at the end of the number.

about 4 years ago · Juan Pablo Isaza
2 Respuestas
Responde la pregunta

0

The problem is that the if statements you have, are returning you false, so you are not making the parseInt, if you take them out, it works correctly:

    function doslope() {
            var b, m;
            x1 = parseFloat(5);
            y1 = parseFloat(5);
            x2 = parseFloat(6);
            y2 = parseFloat(3);
            m = (y2 - y1) / (x2 - x1);
            b = y1 - m * x1;
            m = m.toFixed(2);
            b = b.toFixed(2);

            m = parseInt(m.toString());

            b = parseInt(b.toString());

            document.getElementById("result").innerHTML = "y=" + m + "x+" + b;
    }

Why are you using that if statement?

If you want that the user can only put numbers, you can try with something like this: type="number" just allows to put numbers, and step="0.01" allows you to put decimal numbers

<label>x1<input id="x1" type="number" step="0.01" /></label><br>
<label>y1<input id="y1" type="number" step="0.01" /></label><br>
<label>x2<input id="x2" type="number" step="0.01" /></label><br>
<label>y2<input id="y2" type="number" step="0.01" /></label><br>
about 4 years ago · Juan Pablo Isaza Denunciar

0

Number.isInteger() checks the type of the value and since your m and b variables are string it will always return false. What you could do is temporarily convert them into float:

  if (Number.isInteger(parseFloat(m))) {
    m = parseInt(m.toString());
  }

Alternatively (and in your case I think would be a better option) is to simply remove .00 from the string itself:

  m = m.toFixed(2).replace(/\.?0+$/, '');
  b = b.toFixed(2).replace(/\.?0+$/, '');
about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda