Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

385
Vistas
Firebase addDoc not writing data to Firestore

I'm trying to write some data to my Firestore database. I've been following Firebase docs but for some reason nothing is being written to my database. I'm not receiving any console errors but there are no new docs being written. I've also tried using setDoc, but no luck with that either.

import { initializeApp } from "https://www.gstatic.com/firebasejs/9.6.8/firebase-app.js";
import { getFirestore, doc, setDoc, addDoc, collection } from "https://www.gstatic.com/firebasejs/9.6.8/firebase-firestore.js";

const firebaseConfig = {
   ...
};

// Initialize Firebase
const app = initializeApp(firebaseConfig);
const db = getFirestore();

var submitPost = document.getElementById("submitPost");

submitPost.addEventListener("click", writeToDB, false);

async function writeToDB() {
   console.log("HIT ME")
   const newDoc = await addDoc(collection(db, 'posts'), {
       test: 'TEST',
       please: 'WORK',
   });
};

Here is my Firestore console after running the function, it does not contain any new documents, only one I have already made manually: enter image description here

about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

when you use async/await syntax instead .then() make sure to put a try/catch around your await to capture any possible error in your Promise.

  async function writeToDB() {
    console.log("HIT ME")
    try {
      const newDoc = await addDoc(collection(db, 'posts'), {
        test: 'TEST',
        please: 'WORK', });

    } catch(err) {
      console.error("writeToDB failed. reason :", err)
    }
  };

if you don't enclose it in try/catch any promise fail will be silent. And it would be equivalent of not having .catch() after .then()

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda