Use this regex:

const regex = /\('([^']+)',\)/g

const output = input.replace(regex, '$1');

//   explain:  /  \(  '  (   [^']+  )  ',\)  /  g

//             1   2  3  4    5     6   7    8  9

• 1: start regex
• 2: match character ( (character / to escape)
• 3: match character '
• 4: start group in regex
• 5: match character not '
• 6: close group in regex
• 7: match ',)
• 8: end regex
• 9: make this regex match global (don't need if you want replace one time)
• $1 in code is first group match regex (start with 4 and end with 6)

const input = `('FCA',)
('JP NIC',)
('JP CHI',)
('2022-03-04T07:18:36.468Z',)`;

const output = input.replace(/\('([^']+)',\)/g, '$1');

console.log(input)
console.log('// =>')
console.log(output)

you can use regex and string.replace

string.replace(/[|&;$%@"<>()+,]/g, "");

just put whatever string you want to ignore inside the rectangular brackets, i.e - string.replace(/[YOUR_IGNORED_CHARACTERS]/g, "")

you can read more about regex here

You could use a regex replacement with a capture group:

var inputs = ["('FCA',)", "('JP NIC',)", "('JP CHI',)", "('2022-03-04T07:18:36.468Z',)"];
var outputs = inputs.map(x => x.replace(/\('(.*?)',\)/g, "$1"));
console.log(outputs);