Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

134
Vistas
JavaScript Reduce with Objects

This is my object

   let products = [
      { "productName": "A", "storage": "Lot 1", "quantity": 1000, "status": "stockIn" },
      { "productName": "A", "storage": "Lot 1", "quantity": 100, "status": "stockIn"  },
      { "productName": "A", "storage": "Lot 1", "quantity": 500, "status": "stockOut" },
      { "productName": "A", "storage": "Lot 2", "quantity": 500, "status": "stockIn"  }
   ]

This is what I am trying to achieve

   let result = [
      { "productName": "A", "storage": "Lot 1", "stockIn": 1100, "stockOut": 500, "available":600 },
      { "productName": "A", "storage": "Lot 2", "stockIn": 500, "stockOut": 0, "available":500   }
   ]

Please kindly provide an idea on how to achieve this without redundant codes. Thanks

var storage = new Set(products.map(item => item.storage));

storage.forEach(lot => {

var stockIn = products.filter(item => item.storage === storage && item.status == 'stockIn')
    .map(({ storage, quantity }) => ({ storage, quantity }));

var stockInSum = stockIn.reduce((prev, curr, index) => prev + curr.quantity, 0);

var stockOut = products.filter(item => item.storage === storage && item.status == 'stockOut')
    .map(({ storage, quantity }) => ({ storage, quantity }))

var stockOutSum = stockOut.reduce((prev, curr, index) => prev + curr.quantity, 0);

}
about 4 years ago · Juan Pablo Isaza
2 Respuestas
Responde la pregunta

0

  • Using Array#reduce, iterate over the array while updating a Map where the key is the combination of productName and storage, and the value is the corresponding grouped object
  • In every iteration, using the current key, get the pair if exist and deconstruct stockIn and stockOut. According to the current status, update one of the latter values and compute available. Finally, using Map#set, create/update the pair.
  • Using Map#values, get the list of grouped objects

const products = [
  { productName: "A", storage: "Lot 1", quantity: 1000, status: "stockIn" },
  { productName: "A", storage: "Lot 1", quantity: 100,  status: "stockIn"  },
  { productName: "A", storage: "Lot 1", quantity: 500,  status: "stockOut" },
  { productName: "A", storage: "Lot 2", quantity: 500,  status: "stockIn"  }
];

const result = [...
  products.reduce((map, { productName, storage, quantity, status }) => {
    const key = `${productName}-${storage}`;
    let { stockIn = 0, stockOut = 0 } = map.get(key) ?? {};
    if(status === 'stockIn') stockIn += quantity;
    else stockOut += quantity;
    const available = stockIn - stockOut;
    map.set(key, { productName, storage, stockIn, stockOut, available });
    return map;
  }, new Map)
  .values()
];

console.log(result);

about 4 years ago · Juan Pablo Isaza Denunciar

0

Here is the general pattern. I will leave it to you to figure out the other fields.

const reduced = products.reduce( (a,v) => {
  const found = a.find(it=>it.lot === v.lot && it.productName === v.productName)
  if (found) {
    a.quantity += v.quantity
    // aggregate your other fields here.
  }
  else {
    a.push(v)
  }
  return a
}, [] )
about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda