I have an array as shown below, containing 6 numbers. I'm trying to create a function that deletes a value if it's an even/odd occurance. For example, if I type the function deleteData(myArr,"even"), it will remove data number 0th, 2nd, and 4th. And the other way around if it's "odd". But when I tried running my code, it didn't work the way i wanted it to go. Can anybody tell me why?
const myArr=[90,34,28,19,26,22];
function deleteData (array,occuranceType){
switch (occuranceType){
case "odd":
for (let i=0;i<array.length;i++){
if (i%2!==0){
array.splice(i,1);
};
};
break;
case "even":
for (let i=0;i<array.length;i++){
if (i%2==0){
array.splice(i,1);
};
};
break;
};
};
deleteData(arr,"odd")
console.log(arr)
This is the result in the console : [ 90, 28, 19, 22 ]
You can use filter for this since it's easier and you don't mutate the original array.
let myArr = [90, 34, 28, 19, 26, 22];
function deleteData(array, removeEven) {
return array.filter((v, i) => removeEven ? (i % 2 !== 0) : (i % 2 === 0));
};
myArr = deleteData(myArr, true)
console.log(myArr)You can filter the array based on the pos argument passed to the function.
const deleteData = (array, pos) =>
array.filter((_, i) => i % 2 === Number(pos !== "even"));
console.log(deleteData([90, 34, 28, 19, 26, 22], "odd"));
console.log(deleteData([90, 34, 28, 19, 26, 22], "even"));Note: Number(false) returns 0 and Number(true) returns 1.