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Sum specific properties values of objects in array if they have same property name and return unique array as result using java script

my problem is to map two array of objects and sum their specifics properties if they have same name value.

For example if I would like to sum x and y of all objects where property name is 'v' etc. Here is my code

var arr = [{name:'v', x:1, b:2, c:3},{name:'r', x:2, b:0, c:3},{name:'v', x:4, b:3, c:3}, {name:'v', x:1, b:1, c:3}];
let arr2 = []
let obj = {name:null, x:null, b: null, c:null}
arr.map(item => {
for(let i=0; i<= arr.length; i++){

    if(item.name === arr[i].name){
     let a = arr.reduce((a, b) => ({x: a.x + b.x, b: a.b + b.b})); 
      obj.name = item.name, obj.x = a.x, obj.b = a.b, obj.c = item.c
    } else {
    obj.name = item.name, obj.x=item.x, obj.b=item.b, obj.c=item.c
        }
  arr2.push(obj)
        }
  }
)

console.log(arr2)

As result i would like to return array like this

arr2 = [{name: 'v', x: 6, b: 6, c: 3}, {name: 'r', x:2, b:0, c:1}]
about 4 years ago · Juan Pablo Isaza
2 Respuestas
Responde la pregunta

0

const sumProperties = (arr) => {
  const result = [];
  const map = new Map();
  for (const obj of arr) {
    const key = obj.name;
    if (!map.has(key)) {
      map.set(key, obj);
    } else {
      const oldObj = map.get(key);
      const newObj = { ...oldObj, ...obj };
      map.set(key, newObj);
    }
  }
  map.forEach((value) => {
    result.push(value);
  });
  return result;
}
console.log(sumProperties(arr));
about 4 years ago · Juan Pablo Isaza Denunciar

0

Here is the answer for my question

var arr = [{v:'v', x:1, b:2, c:3},{v:'r', x:2, b:0, c:3},{v:'v', x:4, b:3, c:3},{v:'v', x:10, b:3, c:3},{v:'r', x:1, b:1, c:3},{v:'v', x:11, b:2, c:3},{v:'r', x:22, b:0, c:3}];
let arr2 = []
for(let j=0; j< arr.length;j++){
    for(let i=j+1; i< arr.length; i++){
        let obj = {v:null, x:null, b: null, c:null}
        if(arr[j].v === arr[i].v ){
          let a =  arr.filter(({v})=> v === arr[j].v).reduce((a, b) => ({x: a.x + b.x, b: a.b + b.b})); 
        obj.v = arr[j].v
        obj.x = a.x 
        obj.b = a.b 
        obj.c = arr[j].c  
        i= arr.length
        console.log("DA", obj)
        if(!arr2.some(item=> item.v === obj.v)){
            arr2.push(obj)
        }
    } else if(i+1 === arr.length){  
        obj.v = arr[j].v 
        obj.x = arr[j].x 
        obj.b = arr[j].b 
        obj.c = arr[j].c
        console.log("NE", obj)
        if(!arr2.some(item=> item.v === obj.v)){
            arr2.push(obj)
            }
        }
    }
}
console.log(arr2, "REZ")

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
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