There are many options in javascript, but are there any options in typescript to do the find words in a given string:
Eg:
For the list: ['Mr', 'Mrs', 'FM.', 'Sir'] and a string called 'Sir FM. Sam Manekshaw'. I have the words 'Sir' and 'FM.' present, hence needs to be assigned to a string and the remaining parts of the string assigned to another string. i.e:
a = Sir FM.
b = Sam Manekshaw
NOTE: It should validate only full words and not a substring.
UPDATE: What I tried:
var tempPrefixList = ['Mr', 'Mrs', 'FM.', 'Sir'];
var firstName = "Sir FM. Sam Manekshaw";
var prefixSearchExp = new RegExp(tempPrefixList.join("|"),"gi");
if(firstName && prefixSearchExp.test(firstName)) {
console.log("Caught");
var requestFirstNameSplit = firstName?.split(" ");
console.log("Prefix: " + requestFirstNameSplit[0]);
console.log("First name: " + requestFirstNameSplit[1]);
}
But this considers only if the name has one Prefix. And also, has only one name in firstName. Eg: Sir Sam. But doesn't work for the example I mentioned earlier.
You can solve it like this:
class PersonDetails {
formOfAddress: string;
name: string;
constructor(formOfAddress: string, name: string) {
this.formOfAddress = formOfAddress;
this.name = name;
}
get fullName(): string {
return [this.formOfAddress, this.name].join(' ');
}
}
function extractPersonDetailsFromFullName(fullName: string): PersonDetails {
const formOfAddresses = ['Mr', 'Mrs', 'FM.', 'Sir'];
let usedFormOfAddresses = [];
const wordsInName = fullName.split(' ').filter((x) => x);
for (const word of wordsInName ?? []) {
if (formOfAddresses.filter((foa) => foa == word).length == 1) {
usedFormOfAddresses.push(word);
}
}
const formOfAddress = usedFormOfAddresses.join(' ');
return new PersonDetails(
formOfAddress,
fullName.substr(formOfAddress.length).trim()
);
}
const testNames = ['Sir FM. Sam Manekshaw', 'Mr Tom'];
for (const testName of testNames) {
const personDetails = extractPersonDetailsFromFullName(testName);
appDiv.innerHTML +=
testName +
' => <br> ' +
JSON.stringify(personDetails) +
'<br><br>';
}
Code: https://stackblitz.com/edit/typescript-iyk3ul?file=index.ts
If you don't want to use the implementation with the separate function and object, you can use the following code:
const fullName = 'Sir FM. Sam Manekshaw';
const formOfAddresses = ['Mr', 'Mrs', 'FM.', 'Sir'];
let formOfAddressParts = [];
let nameParts = [];
const wordsInName = fullName.split(' ').filter((x) => x);
for (const word of wordsInName ?? []) {
if (formOfAddresses.filter((foa) => foa == word).length == 1) {
formOfAddressParts.push(word);
} else {
nameParts.push(word);
}
}
let formOfAddress = formOfAddressParts.join(' ');
let name = nameParts.join(' ');
console.log('formOfAddress: ', formOfAddress);
console.log('name: ', name);