I am looking to randomly select a number from this array WITHOUT duplicates. There can only be two possibilities for each number as shown in the array, select up to a maximum of 6. This works to select a random number but allows duplicates...
const smallNums = [1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10];
const randomSmallNumArr = smallNums[Math.floor(Math.random() * smallNums.length)];
When using the splice() method, each time I generate a number based on a random index, it's removed but shows up again in the array the next time a random is generated
Use a Set to get the unique items in the array.
const smallNums = [...new Set([1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10])]
const randomSmallNumArr = smallNums[Math.floor(Math.random() * smallNums.length)];
console.log(randomSmallNumArr)If I understand your requirement clearly, You want to generate a non-repeating random numbers from an array of numbers ? If Yes, I added a solution below.
// Input array
const arr = [1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10];
// Remove duplicate elements from an array
let uniqueElementsArr = [...new Set(arr)];
// Find out random number from an array
const randomNum = uniqueElementsArr[Math.floor(Math.random()*uniqueElementsArr.length)];
// removing the random number from the existing array so that it should not be replicate.
if (uniqueElementsArr.indexOf(randomNum) !== -1) {
uniqueElementsArr.splice(uniqueElementsArr.indexOf(randomNum), 1)
}
console.log(randomNum);