0
218
VisualizaçõesTernary Operator not yielding expected result
In JavaScript: I have a ternary operator being instructed to return a tip percentage of %15 if the bill amount is between $50-300, otherwise being instructed to reuturn a tip percentage of %20. On a bill amount of $275, it is still yielding %20. I have looked at many examples of functioning ternary operators and my code seems to be properly worded and yet the result comes out incorrect every time. In what way am I failing?
const bill_1 = 40;
const bill_2 = 275;
const bill_3 = 430;
let bill;
let tip_percentage = bill >= 50 && bill <= 300 ? 0.15 : 0.2;
bill = bill_1;
console.log(`The first table's bill came out to $${bill}. After the tip of ${tip_percentage}% (equalling: $${bill * tip_percentage}) was added, the final amount owed is: $${bill * tip_percentage + bill}`);
bill = bill_2;
console.log(`The second table's bill came out to $${bill}. After the tip of ${tip_percentage}% (equalling: $${bill * tip_percentage}) was added, the final amount owed is: $${bill * tip_percentage + bill}`);
bill = bill_3;
console.log(`The third table's bill came out to $${bill}. After the tip of ${tip_percentage}% (equalling: $${bill * tip_percentage}) was added, the final amount owed is: $${bill * tip_percentage + bill}`);
This is the result being given:
·
Juan Pablo Isaza
2 Respostas
Responde à pergunta0
As @Matt said in the comment, tip_percentage is not a function and must be calculated each time you change the bill amount.
Try this:
const bill_1 = 40;
const bill_2 = 275;
const bill_3 = 430;
function getTip(bill) {
var tip = (bill >= 50 && bill <= 300) ? 0.15 : 0.2;
return tip;
}
alert(`Bill one's tip: ${getTip(bill_1)}`);
alert(`Bill two's tip: ${getTip(bill_2)}`);
alert(`Bill two's tip: ${getTip(bill_3)}`);
·
Juan Pablo Isaza
Relatório
0
tip_percentage is already calculated.
If you want to make different result values depending on the variable, make them in the form of functions.
const bill_1 = 40;
const bill_2 = 275;
const bill_3 = 430;
const tip_percentage = (bill) => (bill >= 50 && bill <= 300 ? 0.15 : 0.2);
const printTipResult = (bill) => {
console.log(`The third table's bill came out to $${bill}.
After the tip of ${tip_percentage(bill)}%
(equalling: $${bill * tip_percentage(bill)}) was added,
the final amount owed is: $${bill * tip_percentage(bill) + bill}`);
};
printTipResult(bill_1);
printTipResult(bill_2);
printTipResult(bill_3);
·
Juan Pablo Isaza
Relatório
Responde à pergunta