I have 2 arrays one is "searchEachIndex" and another one is "data".
Based on "searchEachIndex" array i want to filter the "data" array. i.e,
Here in searchEachIndex array i have 123 value that matches with data array's employeId.
should push the object into res array here { id: 2, employeId: 123 }, { id: 3, employeId: 123 }, If both values matches. otherwise push the mismatching searchEachIndex values here 1234, 12 into another array i.e, noData array.
let searchEachIndex = [123, 1234, 12]
let data = [
{
id: 1,
employeId: 121
},
{
id: 2,
employeId: 123
},
{
id: 3,
employeId: 123
}
];
let res=[];
let noData = [];
searchEachIndex.forEach(val => {
data.map(item => {
if(item.employeId === val) {
res.push(item)
}
})
})
console.log('Both emp id and searchEachIndex value matched array', res);
consolelog('Ids not found array', noData);
Actually i need response like the following : res : [{ id: 2, employeId: 123 }, { id: 3, employeId: 123 }] and noData : [1234, 12]
You can substitute the .map with .forEach since you do not require a transformed array returned and are only looking for a for loop.
Also you can keep a boolean flag which lets you know if the current val had a corresponding entry in the data array. That way you can push (/not push) into your noData array.
Building up on your code :
let searchEachIndex = [123, 1234, 12]
let data = [
{
id: 1,
employeId: 121
},
{
id: 2,
employeId: 123
},
{
id: 3,
employeId: 123
}
];
let res=[];
let noData = [];
searchEachIndex.forEach(val => {
let found = false;
data.forEach(item => {
if(item.employeId === val) {
found = true;
res.push(item)
}
})
if(!found) noData.push(val);
})
console.log('Both emp id and searchEachIndex value matched array', res);
console.log('Ids not found array', noData);You could take an object to keep track of used values and filter the arrays.
const
search = [123, 1234, 12],
used = Object.fromEntries(search.map(k => [k, false])),
data = [{ id: 1, employeId: 121 }, { id: 2, employeId: 123 }, { id: 3, employeId: 123 }],
result = data.filter(({ employeId }) => {
if (employeId in used) return used[employeId] = true;
}),
noData = search.filter(k => !used[k]);
console.log(noData);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }