I have a bunch array of objects with participants and messages, I want to filter the object with the below array of two participants, can anyone help with this
this is the example participnats of array :
["61badffe4ccf060b329441e0","61bc33a84ccf060b32944354"]
bunch of sample messages and participants :
{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61bae01b4ccf060b329441ef"
],
"_id": "61bae0394ccf060b329441fb",
},
{
"messages": [],
"participants": [
"61bae1014ccf060b3294420e",
"61bae01b4ccf060b329441ef"
],
"_id": "61bb230c4ccf060b3294421c"
},
{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61bc33a84ccf060b32944354"
],
"_id": "61d476dff651471663a72971",
},
{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61e54b82eab592e7fef65656"
],
"_id": "61e54ba3eab592e7fef6567a",
]
**expected below object after filter participants:**
```{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61bc33a84ccf060b32944354"
],
"_id": "61d476dff651471663a72971",
},
You might wanna use Array.filter() and also in your case you should check every element from that array which should match your criteria.
const input = [{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61bae01b4ccf060b329441ef"
],
"_id": "61bae0394ccf060b329441fb",
},
{
"messages": [],
"participants": [
"61bae1014ccf060b3294420e",
"61bae01b4ccf060b329441ef"
],
"_id": "61bb230c4ccf060b3294421c"
},
{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61bc33a84ccf060b32944354"
],
"_id": "61d476dff651471663a72971",
},
{
"messages": [],
"participants": [
"61badffe4ccf060b329441e0",
"61e54b82eab592e7fef65656"
],
"_id": "61e54ba3eab592e7fef6567a",
}
];
const filterByParticipants = ["61badffe4ccf060b329441e0","61bc33a84ccf060b32944354"];
const output = input.filter(el => el.participants.every(el => filterByParticipants.includes(el)));
console.log(output);You need to use filter() method of Array Object, to filter it based on certain conditions.
You can then use every() method of participants array, to check if every participant is present in the object.
let obj=[{messages:[],participants:["61badffe4ccf060b329441e0","61bae01b4ccf060b329441ef"],_id:"61bae0394ccf060b329441fb"},{messages:[],participants:["61bae1014ccf060b3294420e","61bae01b4ccf060b329441ef"],_id:"61bb230c4ccf060b3294421c"},{messages:[],participants:["61badffe4ccf060b329441e0","61bc33a84ccf060b32944354"],_id:"61d476dff651471663a72971"},{messages:[],participants:["61badffe4ccf060b329441e0","61e54b82eab592e7fef65656"],_id:"61e54ba3eab592e7fef6567a"}];
let participants =["61badffe4ccf060b329441e0","61bc33a84ccf060b32944354"];
let res = obj.filter((o)=>{
let oParticipants = o.participants;
let out = participants.every(p => oParticipants.includes(p))
return out;
});
console.log(res)