I have a function that returns the guilds prefix in Discord.JS:
getprefix.js:
const GuildSchema = require("../Database/Models/GuildConfigs");
const { DEFAULT } = require("./config");
const getprefix = async (id) => {
const guildConfigs = await GuildSchema.findOne({
GuildID: id,
});
let PREFIX = DEFAULT;
if (guildConfigs && guildConfigs?.Prefix) {
PREFIX = guildConfigs?.Prefix;
}
};
module.exports = { getprefix };
I call the function in another file using this:
let prefix = getprefix(message.guild.id);
prefix.then(() => {
console.log(prefix);
});
The problem is it returns this in the console:
Promise { '!' }
Is it possible to just return the actual prefix that is inside the quotes with out the Promise?
Yes, but you must return the value from the async function.
getprefix.js:
const GuildSchema = require("../Database/Models/GuildConfigs");
const { DEFAULT } = require("./config");
const getprefix = async (id) => {
const guildConfigs = await GuildSchema.findOne({
GuildID: id,
});
let PREFIX = DEFAULT;
if (guildConfigs && guildConfigs?.Prefix) {
PREFIX = guildConfigs?.Prefix;
}
return PREFIX;
};
module.exports = { getprefix };
and change the call:
let prefix = getprefix(message.guild.id);
prefix.then((value) => {
console.log(value);
});
First you must return a value from your async function called getprefix. Secondly you must console.log the result of the promise returned by getprefix function instead of the promise itself :
const getprefix = async (id) => {
const guildConfigs = await GuildSchema.findOne({GuildID: id});
if (!guildConfigs || !guildConfigs.Prefix) {
return DEFAULT;
}
return guildConfigs.Prefix;
};
getprefix(message.guild.id).then(prefix => console.log(prefix));