I found another question similar to the one I have, but I was not able to replicate it (probably because it doesn't deal with hashes neither have symbols).
So, given the following array of hashes:
[{:id=>1, :name=>"AA;AB;AC", :title=>"A row"},
{:id=>2, :name=>"BA;BB", :title=>"B row"},
{:id=>3, :name=>"CA", :title=>"C row"}]
I would like to achieve the following result:
[{:id=>1, :name=>"AA", :title=>"A row"},
{:id=>1, :name=>"AB", :title=>"A row"},
{:id=>1, :name=>"AC", :title=>"A row"},
{:id=>2, :name=>"BA", :title=>"B row"},
{:id=>2, :name=>"BB", :title=>"B row"},
{:id=>3, :name=>"CA", :title=>"C row"}]
In brief, I want to fully replicate a hash, splitting it by semicolon. In this case, :name have two hashes with one or more semicolons that should be split and consist on another hash.
I hope you have understand my question. Any help is highly appreciated.
You could iterate over your array of hashes and split their name value, and map that result merging it with the current hash. Then you can flatten the result:
[
{:id=>1, :name=>"AA;AB;AC", :title=>"A row"},
{:id=>2, :name=>"BA;BB", :title=>"B row"},
{:id=>3, :name=>"CA", :title=>"C row"}
].flat_map do |hsh|
hsh[:name].split(";").map do |name|
hsh.merge(name: name)
end
end
# [{:id=>1, :name=>"AA", :title=>"A row"},
# {:id=>1, :name=>"AB", :title=>"A row"},
# {:id=>1, :name=>"AC", :title=>"A row"},
# {:id=>2, :name=>"BA", :title=>"B row"},
# {:id=>2, :name=>"BB", :title=>"B row"},
# {:id=>3, :name=>"CA", :title=>"C row"}]
Using Enumerable#each_with_object
ary =
[
{ id: 1, name: "AA;AB;AC", title: "A row" },
{ id: 2, name: "BA;BB", title: "B row" },
{ id: 3, name: "CA", title: "C row" }
]
ary.each_with_object([]) do |hash, new_ary|
hash[:name].split(";").each do |name|
new_ary << hash.merge(name: name)
end
end