I need to be able to return nil when I can't find is_my_favorite? to have a value of true, and return the hash that is the favorite. My current code will return the hash that is true, but if they were all false for example, I want to return nil, but I can't come up with a way of doing so without breaking my code, which currently does half of what I want.

# array_of_hash_objects will look something like this:
  # [
  #   { name: 'Ruby', is_my_favorite?: true },
  #   { name: 'JavaScript', is_my_favorite?: false },
  #   { name: 'HTML', is_my_favorite?: false }
  # ]
  array_of_hash_objects.each do |item|
    item.each do |words|
      if words.one?(true)
        return item
    
        
      end
    end
  end
end

I've tried this:

  array_of_hash_objects.each do |item|
    item.each do |words|
      if words.one?(true)
        return item
      else
        return nil
    
        
      end
    end
  end
end

but this returns

Failure/Error: expect(find_favorite(array)).to eq(expected_output)

   expected: nil
        got: [{:is_my_favorite?=>false, :name=>"Python"}, {:is_my_favorite?=>false, :name=>"JavaScript"}, {:is_my_favorite?=>false, :name=>"HTML"}]