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Nested array mapping and filtering in javascript

I am designing a system and I have some bottlenecks.

I have user array such like that:

 const users = [
  {
    name: "Jack",
    workspaces: [
      {
        _id: "61216512315615645jbk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
      {
        _id: "41ss16512315615645bk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
    ],
  },
  {
    name: "Joe",
    workspaces: [
      {
        _id: "71216512315615645jbk",
        permissions: ["CAN_DELETE_WORKSPACE"],
      },
    ],
  },
];

And I have activeWorkspace object such like that:

const activeWorkspace = {
  name: "W1",
  _id: "61216512315615645jbk",
};

I need to filter the objects in the users array whose workspace _id is equal to activeWorkspace _id.

Output must be like that:

{
    name: "Jack",
    workspaces: [
      {
        _id: "61216512315615645jbk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
      {
        _id: "41ss16512315615645bk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
    ],
}

How can I do that?

In addition: If we want to return an array, not an object, how should we do it? Like that:

[{
        name: "Jack",
        workspaces: [
          {
            _id: "61216512315615645jbk",
            permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
          },
          {
            _id: "41ss16512315615645bk",
            permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
          },
        ],
}]

Thanks

about 4 years ago · Juan Pablo Isaza

3 Respostas

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Answer 1 · 2022-07-09T02:34:50.074Z

If there is only one match. You need to use find(). Inside of the find method, you want to use some() to look for an _id match.

 const users = [
  {
    name: "Jack",
    workspaces: [
      {
        _id: "61216512315615645jbk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
      {
        _id: "41ss16512315615645bk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
    ],
  },
  {
    name: "Joe",
    workspaces: [
      {
        _id: "CHANGED_ID",
        permissions: ["CAN_DELETE_WORKSPACE"],
      },
    ],
  },
];

const activeWorkspace = {
  name: "W1",
  _id: "61216512315615645jbk",
};

const active = users.find(function (user) {
  return user.workspaces.some( function (workspace) {
    return workspace._id === activeWorkspace._id;
  });
});

console.log(active);


// Same thing as above, just done with a modern approach
const active2 = users.find(({workspaces}) => workspaces.some(({_id}) => _id === activeWorkspace._id));

console.log(active2);

Now if there could be more than one match (your orginal code before the typo, you would use filter() and some() to find all users that have the workspace in their array.

 const users = [
  {
    name: "Jack",
    workspaces: [
      {
        _id: "61216512315615645jbk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
      {
        _id: "41ss16512315615645bk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
    ],
  },
  {
    name: "Joe",
    workspaces: [
      {
        _id: "61216512315615645jbk",
        permissions: ["CAN_DELETE_WORKSPACE"],
      },
    ],
  },
];

const activeWorkspace = {
  name: "W1",
  _id: "61216512315615645jbk",
};

const active = users.filter(function (user) {
  return user.workspaces.some( function (workspace) {
    return workspace._id === activeWorkspace._id;
  });
});

console.log(active);


// Same thing as above, just done with a modern approach
const active2 = users.filter(({workspaces}) => workspaces.some(({_id}) => _id === activeWorkspace._id));

console.log(active2);

Answer 2 · 2022-07-09T02:34:50.084Z

I adjusted the provided data from Joe so he doesn't have permissions

const users = [{
    name: "Jack",
    workspaces: [{
        _id: "61216512315615645jbk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
      {
        _id: "41ss16512315615645bk",
        permissions: ["CAN_DELETE_WORKSPACE", "CAN_EDIT_PROJECT"],
      },
    ],
  },
  {
    name: "Joe",
    workspaces: [{
      _id: "61216512315615645bk",
      permissions: ["CAN_DELETE_WORKSPACE"],
    }, ],
  },
];

const activeWorkspace = {
  name: "W1",
  _id: "61216512315615645jbk",
};

function findPermittedUser() {
  return users.filter(user => {
    let hasPermission = false

    user.workspaces.forEach(workspace => {
      if (activeWorkspace._id == workspace._id) {
        hasPermission = true
      }
    })

    return hasPermission
  })
}


console.log(findPermittedUser())

Answer 3 · 2022-07-09T02:34:50.093Z

You can use map and filter to "filter" out the unwanted ids from the users object. Something like :

const users = [
    {
        "name": "Jack",
        "workspaces": [
            {
                "_id": "61216512315615645jbk",
                "permissions": [
                    "CAN_DELETE_WORKSPACE",
                    "CAN_EDIT_PROJECT"
                ]
            },
            {
                "_id": "41ss16512315615645bk",
                "permissions": [
                    "CAN_DELETE_WORKSPACE",
                    "CAN_EDIT_PROJECT"
                ]
            }
        ]
    },
    {
        "name": "Joe",
        "workspaces": [
            {
                "_id": "61216512315615645jbk",
                "permissions": [
                    "CAN_DELETE_WORKSPACE"
                ]
            }
        ]
    }
]

const activeWorkspace = {
  name: "W1",
  _id: "61216512315615645jbk",
};


const filteredUsers = users.map(item => ({ 
  name : item.name, 
  workspaces: item.workspaces.filter(user => user._id === activeWorkspace._id)}
));

console.log(filteredUsers);

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Nested array mapping and filtering in javascript

3 Respostas

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Encontrar trabalhos remotos

Andres GPT