So I've been trying to rewrite a Ruby snippet of code into Python, and I haven't been able to make it work. I reread everything to make sure I did it right, but it still doesn't work. I guess the problem lies in this "translation":
def multiply(k, point = $G)
current = point
binary = k.to_s(2)
binary.split("").drop(1).each do |char|
current = double(current)
current = add(current, point) if char == "1"
end
current
end
This is my translated python version:
def multiply(k, point = G):
current = point
binary = bin(k)
for i in binary[3:]:
current = double(current)
if i == "1":
current = add(current, point)
return current
I believe I didn't quite understand Ruby's concepts of to_s(2) and/or .drop(1). Could someone tell me what is the best way of translating this Ruby code into Python?
EDIT So, I'll elaborate just as @Michael Butscher suggested:
I have this Ruby code, which I tried to translate into this Python code. And while the output should be
044aeaf55040fa16de37303d13ca1dde85f4ca9baa36e2963a27a1c0c1165fe2b11511a626b232de4ed05b204bd9eccaf1b79f5752e14dd1e847aa2f4db6a5
it throws an error. Why?
The problem is not in the function you have shown, but in your inverse function. / between integers in Ruby translates as // in Python 3:
Ruby:
3 / 2
# => 1
3.0 / 2
# => 1.5
Python 3:
3 / 2
# => 1.5
3 // 2
# => 1