I am using below code for pagination.
<ul className="pagination">
<li className="page-item">
<button className="page-link btn btn-success btn-block" onClick={prev} >Previous</button>
</li>
<li className="page-item">
<button className="page-link btn btn-success btn-block " onClick={next}>Next</button>
</li>
</ul>
const next = () => {
if (page <= lastPage) {
setPage(page + 1);
}
}
const prev = () => {
if (page > 1) {
setPage(page - 1);
}
}
my requirement is when data of first page is getting displayed then prev button should be disabled. when data of lastpage is getting displayed then nextbutton should be disabled.
I mean if(page==1) disableprev and if(page==lastPage)disable next .how can I do it?
You can conditionally disable a button using an expression on the disabled property of the button. For example, for the Previous Button, you can do this,
<button disabled={page == 1} className="page-link btn btn-success btn-block" onClick={prev} >Previous</button>
You can follow the same thing for the Next button too. Just change the expression to page == lastPage
But make sure that the page property is a state of the component so that React automatically refreshes the component when it changes. Regarding your use of setPage I suppose it's already the case
You can implement other methods like disabling the button on page load or something like that, but if you want to keep it simple just add alerts.
NOTE: You had a bug in the first conditional because if you have 50 pages and the actual page is 50, the condition (page <= lastpage) will be true and you will send the user to the page 51 that doesn't exist.
const next = () => {
if (page < lastPage) {
setPage(page + 1);
} else {
alert("This is the last page");
}
}
const prev = () => {
if (page > 1) {
setPage(page - 1);
} else {
alert("This is the first page");
}
}<ul className="pagination">
<li className="page-item">
<button className="page-link btn btn-success btn-block" onClick={prev}>Previous</button>
</li>
<li className="page-item">
<button className="page-link btn btn-success btn-block " onClick={next}>Next</button>
</li>
</ul>