How to return an array with the step of the sum of the previous value?
I have an input number that is 1000 I want to get [1000, 2000, 3000 ... 10000]
I'm trying to:
const range = (i: number, o: number) => {
const arr = [0, 1, 2, 3, 4].reduce(
(accumulator: any, currentValue: any, index: any, array: any) => {
console.log((array[index] = accumulator + currentValue));
return 1;
},
10000
);
};
range(1000, 10000);
Use Array.from and provide the first argument as an object with length property that is equal to the step, and second argument as mapping function that simply multiply the index and step:
const range = (start,end) =>
Array.from( {length: end/start} ,(_,i) => (i+1) * start )
console.log(range(1000,10000))Try this:
function range(start, end) {
var arr = []; // Start with an empty array
/* Start a counter at the start value, and increment it
* by the start value while it is less than or equal to
* the end value. Push this value into arr each time
*/
for (let i = start; i <= end; i += start) {
arr.push(i);
}
return arr; // Return the array
}
Use simple loop and check if number * index <= max while adding values to new array:
const range = (number, max) => {
let index = 1;
let newArray = [];
do {
newArray.push(number * index);
index++;
} while (number * index <= max);
return newArray;
};
console.log(range(1000, 10000));
console.log(range(10000, 10000));