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How can I map a nested array in JS

Here is my array:

const main = [
  [['02:20:21,369'], ['02:20:21,369'], ['02:20:21,369'], ['02:20:21,369']],
  [['02:20:21,369'], ['02:20:21,369']],
  [['02:20:21,369'], ['02:20:21,369'], ['02:20:21,369']],
  [['02:20:21,369']],
];

and here is my function:

const convertor = (x) => {
  const splitted = x.split(':');
  console.log(splitted);
  const converted = splitted[0] * 60 + splitted[1] * 60 + splitted[2];
  return converted;
};

I want to map this function on each nested array

I tried this but I got an error:

const resu = main.map((x) => {
  x.map((y) => {
    convertor(y);
  });
});

x.split is not a function

about 4 years ago · Juan Pablo Isaza

3 Respostas

Responde à pergunta

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Note that there are 3 level nested arrays, so there should be 3 maps()
return is required if you use {} in the arrow function

const main = [
  [['02:20:21,369'], ['02:20:21,369'], ['02:20:21,369'], ['02:20:21,369']],
  [['02:20:21,369'], ['02:20:21,369']],
  [['02:20:21,369'], ['02:20:21,369'], ['02:20:21,369']],
  [['02:20:21,369']],
];

const convertor = (x) => {
  const splitted = x.split(':');
  const converted = splitted[0] * 60 + splitted[1] * 60 + splitted[2];
  return converted;
};

const resu = main.map((x) => {
  return x.map((y) => {
    return y.map((z) => {
      return convertor(z);
    });
  });
});

console.log(resu);

Shorter version

main.map(x => x.map(y => y.map(convertor)));

about 4 years ago · Juan Pablo Isaza Relatório

0

const main = [
  [
    ['02:20:21,369'],
    ['02:20:21,369'],
    ['02:20:21,369'],
    ['02:20:21,369']
  ],
  [
    ['02:20:21,369'],
    ['02:20:21,369']
  ],
  [
    ['02:20:21,369'],
    ['02:20:21,369'],
    ['02:20:21,369']
  ],
  [
    ['02:20:21,369']
  ],
];


const convertor = (x) => {
  const splitted = x.split(':');
  //console.log(splitted);
  const converted = splitted[0] * 60 + splitted[1] * 60 + splitted[2];
  return converted;
};

const mappedMain = main.map(i => {
 return i.map(j => {
  return convertor(...j)
 })
})

//Or
//const mappedMain = main.map(i => i.map(j => convertor(...j)))



console.log(mappedMain);

about 4 years ago · Juan Pablo Isaza Relatório

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Responde à pergunta

Encontrar trabalhos remotos

Accepted Answer · 2022-07-09T08:38:15.227Z

You made some mistakes:

Expression (x) => { /* a few lines of code */ } requires the use of the return keyword to return the result, while (x) => /* single line of code */ doesn't.
Your array main is three-dimensional array, not two-dimensional.

Try this:

const resu = main.map((x) => {
  return x.map((y) => {
    return y.map(convertor);
  });
});

Or easier:

const resu = main.map(
    (x) => x.map(
        (y) => y.map(convertor)
    )
);

const main = [
  [['02:20:21,369'], ['02:20:21,369'], ['02:20:21,369'], ['02:20:21,369']],
  [['02:20:21,369'], ['02:20:21,369']],
  [['02:20:21,369'], ['02:20:21,369'], ['02:20:21,369']],
  [['02:20:21,369']],
];

const convertor = (x) => {
  const splitted = x.split(':');
  const converted = splitted[0] * 60 + splitted[1] * 60 + splitted[2];
  return converted;
};

const resu = main.map(
    (x) => x.map(
        (y) => y.map(convertor)
    )
);

console.log(resu);

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How can I map a nested array in JS

3 Respostas

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Encontrar trabalhos remotos

Andres GPT