I'm studying switch expression, and I'd like to know how to pass control to the invoker method because "yield" just exits from the switch expression. I can't find any way to make it behave like the classic switch statement.
Is it even possible?
UPDATE: Here's a little piece of code.
public static boolean isTimeToParty(DayOfWeek day) {
boolean isParty = switch (day) {
case MONDAY -> false;
case TUESDAY -> {
yield false; //return not allowed
}
case WEDNESDAY -> false;
case THURSDAY -> false;
case FRIDAY -> false;
case SATURDAY -> true;
case SUNDAY -> true;
};
return isParty;
}
What I mean is: How to avoid assigning value to a variable and then calling return [variable_name]? I would like to return value and exit switch at the same time.
Thanks in advance
Simply return to the calling method. If you just want to stop processing further cases in the same switch, use break.
This and the below example apply to the switch statement, whereas the original question was releated to the switch expression.
public static void main(String[] args) throws Exception {
switch(1) {
case 1:
System.out.println("Case one");
// no break, so case processing goes one
case 2:
System.out.println("Case two");
break; // we bail out here and do not process further cases
default:
System.out.println("Default case");
}
switch(2) {
case 2:
return;
default:
System.out.println("Default case");
}
System.out.println("This is the end - should not be printed");
}
generates output
Case one
Case two
As you cannot use return or break within the switch, it would be easier in your case to simplify with return switch ... directly:
public static boolean isTimeToParty(DayOfWeek day) {
return switch (day) {
case SATURDAY, SUNDAY -> true;
default -> false;
};
}