I need to filter an array of objects
const arrayOne = [
{id: 33, name: "fruit"},
{id: 157, name: "car"},
{id: 193, name: "water"},
];
const arrayTwo = [33, 193];
I need only the names in an array (without the key)
Expected output
["fruit", "water"]
1) You can easily achive the result using Map
const arrayOne = [
{ id: 33, name: "fruit" },
{ id: 157, name: "car" },
{ id: 193, name: "water" },
];
const map = new Map();
arrayOne.forEach((o) => map.set(o.id, o.name));
const arrayTwo = [33, 193];
const result = arrayTwo.map((o) => map.get(o));
console.log(result);2) You can also achieve the result using map and find
const arrayOne = [
{ id: 33, name: "fruit" },
{ id: 157, name: "car" },
{ id: 193, name: "water" },
];
const arrayTwo = [33, 193];
const result = arrayTwo.map((id) => arrayOne.find((o) => o.id === id)?.name);
console.log(result);you can just simply do
const arrayOne = [
{ id: 33, name: "fruit" },
{ id: 157, name: "car" },
{ id: 193, name: "water" }
];
const arrayTwo = [33, 193];
let keepResult = [];
arrayOne.map((a1) => {
arrayTwo.map((a2) => {
if (a1.id === a2) {
keepResult.push(a1.name);
}
});
});
console.log("result show", keepResult);const arrayOne = [
{id: 33, name: "fruit"},
{id: 157, name: "car"},
{id: 193, name: "water"},
];
const arrayTwo = [33, 193];
let newArray = arrayOne.filter(item => arrayTwo.includes(item.id)).map(item => item.name)
console.log(newArray);try this