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How to execute two function one by one in the list of functions in the script.sh file

I want two functions called one by one in a single bash command.

I tried by calling in bash
./script run delete_code run stop_node_pool - But it executes first function and stops. second function was not started.
./script delete_code - If we give one function name its work for a particular function. But I need to call two functions that I choose while executing the script in bash.
How to write a program for executing any two functions one by one in a list of functions available in the script.sh file.

My sample code

#!/bin/bash
   
    
    delete_code() { 
    echo "code deleted"
    $1 && shift && "@a"
    }
    
    create_code() { 
    echo "code created"
    $1 && shift && "@a"
            }
    
    stop_node_pool() { 
    echo "node pool stopped"
    $1 && shift && "@a"
    }
    
    start_node_pool() { 
    echo "node pool start"
    $1 && shift && "@a"
    }

EXECUTION 
case $1 in
    delete_code) "$@"; exit;;
    create_code) "$@"; exit;;
    stop_node_pool) "$@"; exit;;
    start_node_pool) "$@"; exit;;

esac

delete_code
create_code
stop_node_pool
start_node_pool

over 4 years ago · Santiago Trujillo

2 Respostas

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Encontrar trabalhos remotos

Answer 1 · 2022-04-13T21:43:33.061Z

I'm not sure I understand your problem (your question is confusing) but perhaps this will solve your issue:

#!/bin/bash

usage() { echo "Usage: $0 <code_deleted|code_created|node_pool_stopped|node_pool_start>" 1>&2; exit 1; }

# unless there are 2 arguments, print the "usage" and exit
[ ! $# -eq 2 ] && usage

# Functions
delete_code() {
    echo "code deleted test"
}

create_code() {
    echo "code created test"
}

stop_node_pool() {
    echo "node pool stopped test"
}

start_node_pool() {
    echo "node pool start test"
}

# Execution
for i in "$@"
do

    case "$i" in

        code_deleted)
            delete_code &
            ;;

        code_created)
            create_code &
            ;;

        node_pool_stopped)
            stop_node_pool &
            ;;

        node_pool_start)
            start_node_pool &
            ;;

        *)
            usage
            ;;
    esac
done
wait

Answer 2 · 2022-04-13T21:43:33.069Z

#!/bin/bash

usage() { echo "Usage: $0 <code_deleted|code_created|node_pool_stopped|node_pool_start>" 1>&2; exit 1; }

# unless there are 2 arguments, print the "usage" and exit
[ ! $# -eq 2 ] && usage

# Functions
delete_code() {
    echo "code deleted test"
}

create_code() {
    echo "code created test"
}

stop_node_pool() {
    echo "node pool stopped test"
}

start_node_pool() {
    echo "node pool start test"
}

# Execution
for i in "$@"
do

    case "$i" in

        code_deleted)
            delete_code &
            ;;

        code_created)
            create_code &
            ;;

        node_pool_stopped)
            stop_node_pool &
            ;;

        node_pool_start)
            start_node_pool &
            ;;

        *)
            usage
            ;;
    esac
wait
done

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How to execute two function one by one in the list of functions in the script.sh file

2 Respostas

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Encontrar trabalhos remotos

Andres GPT