I have a problem on an object inside of an array and I wanted to display only that as an array.
data1
const data1 = [
{
"id": "01",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "fruits"
}
},
{
"id": "02",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "things"
}
}
]
expected output
const final= [
{
"data": "fruits"
},
{
"data": "things"
}
]
Code
const final = data.map((data) => { ...data})
Map through the array and extract its details property:
const data1 = [
{
"id": "01",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "fruits"
}
},
{
"id": "02",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "things"
}
}
]
const res = data1.map(e => e.details)
console.log(res)
map over the array and return a new object using the details property. If you don't return a new object, your new array will still carry references to the objects in the original array. So if you change a value of a property in that original array, that change will be reflected in the new array too, and you probably don't want that to happen.
const data1=[{id:"01",info:"fefef",sub:"hieei",details:{data:"fruits"}},{id:"02",info:"fefef",sub:"hieei",details:{data:"things"}}];
// Make sure you return a copy of the
// details object otherwise if you change the details
// of the original objects in the array
// the new mapped array will carry those object changes
// because the array objects will simply references to the old objects
const out = data1.map(obj => {
return { ...obj.details };
});
console.log(out);
Using map and destructuring will simplify.
const data1 = [
{
id: "01",
info: "fefef",
sub: "hieei",
details: {
data: "fruits",
},
},
{
id: "02",
info: "fefef",
sub: "hieei",
details: {
data: "things",
},
},
];
const res = data1.map(({ details: { data } }) => ({ data }));
console.log(res);
// if you just need the details object
const res2 = data1.map(({ details }) => details);
console.log(res2);