I want to fill the '_' with reference array :
const reference = ['this is', 'a beautiful', 'car'];
const blank = ['I know', '_'];
console.log(fillBlank(reference))
function fillBlank(reference) {
const ref = reference.join(' ');
if(blank.length) {
return // I know this is a beautiful car
} else {
return ref;
}
}Note that we may have blank in different places but we only have one in each blank array:
const blank = ['I know', '_'];
const blank = ['_', 'I know'];
const blank = ['I know', '_', 'right?'];
How can I do this?
You can map and join
const reference = ['this is', 'a beautiful', 'car'];
const ref = reference.join(' ');
const fillBlank = (blank,ref) => blank.map(item => item === "_" ? ref : item).join(", ")
console.log(fillBlank(['I know', '_'],ref))
console.log(fillBlank(['_', 'I know'],ref))
console.log(fillBlank(['I know', '_', 'right?'],ref))We can take this a little step further and uppercase the first letter of the ref if needed
const reference = ['this is', 'a beautiful', 'car'];
const ref = reference.join(' ');
const fillBlank = (blank,ref) => blank.map((item,i) => item === "_" ? i>0? ref : ref.slice(0,1).toUpperCase() + ref.slice(1) : item).join(", ")
console.log(fillBlank(['I know', '_'],ref))
console.log(fillBlank(['_', 'I know'],ref))
console.log(fillBlank(['I know', '_', 'right?'],ref))Try this instead of the 'return // I know this is a beautiful car':
return blank.map(item => item === '_' ? ref : item).join(' ')
function fillBlank(arrToReplace, reference) {
const concatedRef = reference.join(' ');
arrToReplace.splice(arrToReplace.findIndex(el => el === '_'), 1, concatedRef);
return arrToReplace.join(' ');
}