I was reading about arrow function in js. There I found one question.
var arguments = [1, 2, 3];
var arr = () => arguments[2];
console.log(arr());
function foo(n) {
var f = () => arguments[0] + n;
return f();
}
console.log(foo(3));It's output is showing 6. Can anyone explain why it is so?
arguments is the object for getting the arguments of the function called. Therefore arguments[0] is the argument n.
You need to change the name of the array such as arr = [1,2,3] and use it in the foo() function f = () => arr[0] + n;
var arr = [1, 2, 3];
var bar = () => arr[2];
console.log(bar());
function foo(n) {
var f = () => arr[0] + n;
return f();
}
console.log(foo(3));